Euclid's Elements of Geometry: Chiefly from the Text of Dr. Simson, with Appendix by Thos. Kirkland. the first six books |
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Page 8
... greater . It is required to cut off from AB the greater , a part equal to C , the less . D E B F From the point A draw the straight line AD equal to C ; ( 1. 2. ) and from the center A , at the distance AD , describe the circle DEF ...
... greater . It is required to cut off from AB the greater , a part equal to C , the less . D E B F From the point A draw the straight line AD equal to C ; ( 1. 2. ) and from the center A , at the distance AD , describe the circle DEF ...
Page 11
... greater than the other . If possible , let AB be greater than AC ; and from BA cut off BD equal to CA the less , ( 1. 3. ) and join DC . Then , in the triangles DBC , ABC , because DB is equal to AC , and BC is common to both triangles ...
... greater than the other . If possible , let AB be greater than AC ; and from BA cut off BD equal to CA the less , ( 1. 3. ) and join DC . Then , in the triangles DBC , ABC , because DB is equal to AC , and BC is common to both triangles ...
Page 12
... greater than the angle BCD ; ( ax . 9. ) therefore also the angle FDC is greater than the angle BCD ; much more then is the angle BDC greater than the angle BCD . Again , because BC is equal to BD in the triangle BCD , therefore the ...
... greater than the angle BCD ; ( ax . 9. ) therefore also the angle FDC is greater than the angle BCD ; much more then is the angle BDC greater than the angle BCD . Again , because BC is equal to BD in the triangle BCD , therefore the ...
Page 17
... greater than either of the interior opposite angles . Let ABC be a triangle , and let the side BC be produced to D. Then the exterior angle ACD shall be greater than either of the interior opposite angles CBA or BAC . A F B E G Bisect ...
... greater than either of the interior opposite angles . Let ABC be a triangle , and let the side BC be produced to D. Then the exterior angle ACD shall be greater than either of the interior opposite angles CBA or BAC . A F B E G Bisect ...
Page 18
... greater than the angle ECF ; therefore the angle ACD is greater than the angle BAE or BAC . In the same manner , if the side BC be bisected , and AC be pro- duced to G ; it may be demonstrated that the angle BCG , that is , the angle ...
... greater than the angle ECF ; therefore the angle ACD is greater than the angle BAE or BAC . In the same manner , if the side BC be bisected , and AC be pro- duced to G ; it may be demonstrated that the angle BCG , that is , the angle ...
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Common terms and phrases
A₁ ABCD AC is equal Algebraically angle ABC angle ACB angle BAC angle equal Apply Euc base BC chord circle ABC constr describe a circle diagonals diameter divided draw equal angles equiangular equilateral triangle equimultiples Euclid exterior angle Geometrical given circle given line given point given straight line gnomon greater hypotenuse inscribed intersection isosceles triangle less Let ABC line BC lines be drawn multiple opposite angles parallelogram parallelopiped pentagon perpendicular plane polygon produced Prop proportionals proved Q.E.D. PROPOSITION quadrilateral quadrilateral figure radius ratio rectangle contained rectilineal figure remaining angle right angles right-angled triangle segment semicircle shew shewn similar similar triangles solid angle square on AC tangent THEOREM touch the circle triangle ABC twice the rectangle vertex vertical angle wherefore
Popular passages
Page 93 - If a straight line be bisected and produced to any point, the square on the whole line thus produced, and the square on the part of it produced, are together double of the square on half the line bisected, and of the square on the line made up of the half and the part produced. Let the straight line AB be bisected in C, and produced to D ; The squares on AD and DB shall be together double of the squares on AC and CD. CONSTRUCTION. — From the point C draw CE at right angles to AB, and make it equal...
Page 118 - Guido, with a burnt stick in his hand, demonstrating on the smooth paving-stones of the path, that the square on the hypotenuse of a right-angled triangle is equal to the sum of the squares on the other two sides.
Page 145 - If a straight line touch a circle, and from the point of contact a straight line be drawn cutting the circle ; the angles which this line makes with the line touching the circle, shall be equal to the angles which are in the alternate segments of the circle.
Page 88 - If a straight line be divided into two equal parts and also into two unequal parts, the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line.
Page 26 - ... upon the same side together equal to two right angles, the two straight lines shall be parallel to one another.
Page 36 - To a given straight line to apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.
Page 144 - The angle in a semicircle is a right angle ; the angle in a segment greater than a semicircle is less than a right angle ; and the angle in a segment less than a semicircle is greater than a right angle.
Page 92 - If a straight line be divided into two equal, and also into two unequal parts, the squares on the two unequal parts are together double of the square on half the line and of the square on the line between the points of section. Let the straight line AB be divided into two equal parts...
Page xv - In every triangle, the square of the side subtending either of the acute angles is less than the squares of the sides containing that angle, by twice the rectangle contained by either of these sides, and the straight line intercepted between the perpendicular let fall upon it from the opposite angle, and the acute angle.
Page 67 - A proposition affirming the possibility of finding such conditions as will render a certain problem indeterminate or capable of innumerable solutions.