## Mensuration and Practical Geometry: Containing Tables of Weights and Measures, Vulgar and Decimal Fractions, Mensuration of Areas, Lines, Surfaces and Solids. To which is Appended a Treatise on the Carpenter's Slide-rule and Gauging |

### Common terms and phrases

12 inches 20 feet 20 inches angle ascertain the Area ascertain the Contents ascertain the Surface axis base breadth bung and head bung diameter cask Centre of Gravity chord of half Circular Spindle circumference circumscribing circle cone conic section conjugate diameter contents in gallons contents required convex surface cube cubic feet cubic foot cubic inches curve cycloid cylinder decimal denominator diam divided ellipse ends equal eter EXAMPLE EXAMPLE.-The EXAMPLE.-What figure fraction gauge point geometrical centre give the contents given half the arc head diameters hexahedron hyperbola hyperboloid inscribed sphere less abscissa linear edge middle diameter middle frustrum multiply the sum ordinate parabola paraboloid perpendicular plane polygon product will give pyramid quotient radii radius remainder result required RULE RULE.-Multiply sector segment side slant height square feet square root subtract surface required transverse diameter triangle ungula versed sine vertex VULGAR FRACTIONS yards zone

### Popular passages

Page 23 - To reduce a mixed number to an improper fraction. RULE. — Multiply the whole number by the denominator of...

Page 24 - To reduce a whole number to an equivalent fraction, having a given denominator. RULE. Multiply the whole number by the given denominator, and place the product over the said denominator, and it will form the fraction required.

Page 16 - Dry Measure. — 2 pints = 1 quart; 8 quarts = 1 peck; 4 pecks = 1 bushel.

Page 33 - RULE. Divide as in whole numbers, and from the right hand of the quotient point off as many places for decimals as the decimal places in the dividend exceed those in the divisor.

Page 86 - FIND the area of the sector having the same arc with the segment, by the last problem. Find also the area of the triangle, formed by the chord of the segment and the two radii of the sector.

Page 62 - To compute, the area of a regular polygon when the length of a side only is given. RULE. — Multiply the square of the side by the multiplier opposite to the name of the polygon in column A of the following table: — Fig.

Page 28 - Multiply all the numerators together for a new numerator, and all the denominators together for a new denominator.

Page 236 - As the conjugate diameter is to the transverse, so is the square root of the difference of the squares of the ordinate and...

Page 142 - Take out the corresponding area, in the next column on the right hand, and multiply it by the square of the longest chord ; the product will be the area of the zone.