Principles of ArithmeticDeighton, 1885 - 220 pages |
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Page 43
... divisor , and the number of objects in each class the quotient . It will generally be impossible to distribute all the objects equally among the classes . After as many objects as possible have been allotted to each class some objects ...
... divisor , and the number of objects in each class the quotient . It will generally be impossible to distribute all the objects equally among the classes . After as many objects as possible have been allotted to each class some objects ...
Page 46
... divisor on the left - hand side , the quotient on the right , the dividend between them . The product of the quotient and divisor is written underneath the dividend and the remainder underneath this product as in subtraction . But how ...
... divisor on the left - hand side , the quotient on the right , the dividend between them . The product of the quotient and divisor is written underneath the dividend and the remainder underneath this product as in subtraction . But how ...
Page 66
... divisor must be 1 , since only I divides both numbers . With 24 and 35 the operation stands thus : 24 ) 35 ( I 24 II ) 24 ( 2 22 2 ) II ( 5 ΙΟ I ) 2 ( 2 2 We may prove from this an important theorem . If a number is prime to each of two ...
... divisor must be 1 , since only I divides both numbers . With 24 and 35 the operation stands thus : 24 ) 35 ( I 24 II ) 24 ( 2 22 2 ) II ( 5 ΙΟ I ) 2 ( 2 2 We may prove from this an important theorem . If a number is prime to each of two ...
Page 67
... divisors that occur in the operation of finding the G.C.M. of 24 and 35 , we shall have performed the operation of finding the G.C.M. of 17 times 24 and 17 times 35. Since then the last divisor in the former operation was I , the last ...
... divisors that occur in the operation of finding the G.C.M. of 24 and 35 , we shall have performed the operation of finding the G.C.M. of 17 times 24 and 17 times 35. Since then the last divisor in the former operation was I , the last ...
Page 69
... divisors , dividends and re- mainders obtained in the operation for finding the G.C.M. of the first . The work in the two cases will stand thus : 49 ) 63 ( I 49 14 ) 49 ( 3 42 245 ) 315 ( 1 245 70 ) 245 ( 3 210 7 ) 14 ( 2 14 35 ) 70 ( 2 ...
... divisors , dividends and re- mainders obtained in the operation for finding the G.C.M. of the first . The work in the two cases will stand thus : 49 ) 63 ( I 49 14 ) 49 ( 3 42 245 ) 315 ( 1 245 70 ) 245 ( 3 210 7 ) 14 ( 2 14 35 ) 70 ( 2 ...
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Common terms and phrases
2nd Edition 4th Edition addition arithmetical bers centimetres consecutive numbers contain Crown 8vo cube decimal fractions decimal places decimetre difference divisible by 9 divisors English equal number example F. A. Paley Fcap figures find the number finding the G.C.M. five four numbers fourth geometrical geometrical progression George Bell given number greater Greek Hence hundred hundredths Latin least common multiple length M.A. 3rd Edition means millimetres multiply Nicomachus of Gerasa notation number divisible number of combinations number of objects number of permutations number of variations number which divides numbers is equal obtain odd numbers perfect number place further places of decimals Post 8vo prime factors prime numbers prove pyramidal number quotient ratio remainder second number seven shew square inches square root subtract suppose symbols tens tenths thousand thousandths three numbers tion triangular number unaltered unit of measure vulgar fraction whole number words ΙΟ
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