 The lateral area of a frustum of a cone of revolution is equal to the circumference of a section equidistant from its bases multiplied by its slant height.  Solid Geometry - Page 385by Charles Austin Hobbs - 1921 - 192 pagesFull view - About this book
 | William Chauvenet - Geometry - 1871 - 380 pages
...altitudes, or as the squares of the radii of their bases. /"r\ -.vA-.y PROPOSITION VI.— THEOREM. >.. 26. The lateral area of a frustum of a cone of revolution is equal to the half sum of the circumferences of its bases multiplied by its slant height. The plane which cuts... | |
 | William Chauvenet - Geometry - 1872 - 382 pages
...of their altitudes, or as the squares of the radii of their bases. PROPOSITION VI.— THEOREM. 26. The lateral area of a frustum of a cone of revolution is equal to the half sum of the circumferences of its bases multiplied by its slant height. The plane which cuts... | |
 | 1876 - 646 pages
...are mutually equiangular they are also mutually equilateral ; and are either equal or symmetrical. 8. The lateral area of a frustum of a cone of revolution is equal to the half sum of the circumferences of its bases multiplied by its slant height. ENGLISH GRAMMAR. JUNE,... | |
 | George Albert Wentworth - Geometry - 1877 - 416 pages
...frustum of a cone of revolution. Draw CHI-, and AD II, to YY'. Then area AB = AB X 2 jr СH, §662 (the lateral area of a frustum of a cone of revolution is equal to the slant height multiplied 'by the circumference of a section equidistant from its bases). The AABD... | |
 | F. B. Stevens - Examinations - 1884 - 202 pages
...mutually equiangular, they are also mutually equilateral ; and are either equal or symmetrical. 8. The lateral area of a frustum of a cone of revolution is equal to the half sum of the circumferences of its bases multiplied by its slant height. June, 1882. NOTE 1.... | |
 | George Bruce Halsted - Geometry - 1885 - 389 pages
...basal radii rl and r2 find the radius of the circle in which the two cones cut. 329 THEOREM III. 832. The lateral area of a frustum of a cone of revolution is the product of the projection of the frustum s slant height on the axis by twice TT times a perpendicular... | |
 | George Bruce Halsted - Geometry - 1886 - 394 pages
...basal radii r, and r, find the radius of the circle in which the two cones cut. 329 THEOREM III. 832. The lateral area of a frustum of a cone of re-volution is the product of the projection of the frustums slant height on the axis by twice ?r times a perpendicular... | |
 | William Chauvenet, William Elwood Byerly - Geometry - 1887 - 331 pages
...by its slant height. Corollary I. This proposition may be formulated, tf=ir(JB + r}L. Corollary II. The lateral area of a frustum of a cone of revolution is equal to the circumference of a section equidistant from its bases multiplied by its slant height. PROPOSITION... | |
 | William Chauvenet - Geometry - 1889 - 338 pages
...r)L, if R and r are the radii of the bases and L is the slant height. A ^"• 27. COROLLARY II. Tlie lateral area of a frustum of a cone of revolution is equal to the circumference of a section equidistant from its bases multiplied by its slant height. Suggestion.... | |
 | Edward Albert Bowser - Geometry - 1890 - 418 pages
.... L' and S' will approach L and S respectively, as their limits. . • . S = i(C + c)LQED 777. COR. The lateral area of a frustum of a cone of revolution is equal to the circumference of a section equidistant from its bases* multiplied by its slant height. * Called... | |
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