Elements of Plane and Spherical Trigonometry: With Practical Applications |
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Page 85
... middle part is equal to the product of the tangents of the adjacent parts . II . The sine of the middle part is equal to the product of the cosines of the opposite parts . 168. Napier's rules may be proved by showing that they agree ...
... middle part is equal to the product of the tangents of the adjacent parts . II . The sine of the middle part is equal to the product of the cosines of the opposite parts . 168. Napier's rules may be proved by showing that they agree ...
Page 86
... middle part ; then and the complement of h will be the adjacent parts , p and the complement of B the opposite parts , and we have sin ( com . A ) sin ( com . A ) = tan ( com . h ) tan b , cos ( com . B ) cos p ; whence , cos A coth tan ...
... middle part ; then and the complement of h will be the adjacent parts , p and the complement of B the opposite parts , and we have sin ( com . A ) sin ( com . A ) = tan ( com . h ) tan b , cos ( com . B ) cos p ; whence , cos A coth tan ...
Page 87
... hypothenuse h and the oblique angle A ; to solve the triangle . To find p . Make p the middle part , and we have , by Napier's rules , or by ( 200 ) , A sin p = sin A sin h , B C b or , by logarithms , log sin plog sin A BOOK V. 87.
... hypothenuse h and the oblique angle A ; to solve the triangle . To find p . Make p the middle part , and we have , by Napier's rules , or by ( 200 ) , A sin p = sin A sin h , B C b or , by logarithms , log sin plog sin A BOOK V. 87.
Page 88
... middle part , and we have , by Napier's rules , or by ( 202 ) , cos A coth tan b ; whence , tan b tan h cos A , ( 209 ) or , by logarithms , log tan b = log tan h + log cos A. ( 210 ) To find B. Make the complement of h the middle part ...
... middle part , and we have , by Napier's rules , or by ( 202 ) , cos A coth tan b ; whence , tan b tan h cos A , ( 209 ) or , by logarithms , log tan b = log tan h + log cos A. ( 210 ) To find B. Make the complement of h the middle part ...
Page 89
... middle part , and we have , by Napier's rules , or by ( 200 ) , sin p sin A sin h ; whence , sin A = sin P sin h ' ( 213 ) or , by logarithms , log sin A = log sin p ― log sin h . ( 214 ) To find B. Make the complement of B the middle ...
... middle part , and we have , by Napier's rules , or by ( 200 ) , sin p sin A sin h ; whence , sin A = sin P sin h ' ( 213 ) or , by logarithms , log sin A = log sin p ― log sin h . ( 214 ) To find B. Make the complement of B the middle ...
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Common terms and phrases
A B C A+ log acute angle adjacent sides Algebra angle equal angle of elevation angle opposite angle or arc ar.co.log Arithme column headed cos² cosec Cotang decimal denoted divided Elementary Algebra equation Equations Art EXAMPLES feet find the SINE formulæ Geom Geometry given number Given the hypothenuse Greenleaf's New Series half the sum Hence included angle log cos log cot log sin logarithmic cosine logarithmic sine logarithmic tangent M.
M. Sine minus the logarithmic Napier's rules negative oblique oblique-angled spherical triangle Parker's Exercises perpendicular plane triangle Prop right-angled spherical triangle right-angled triangle equal rods School secant side b equal side opposite sin A cos sin A sin sin a+b sin² sine and cosine Solution solve the triangle spherical triangle ABC SPHERICAL TRIGONOMETRY subtract sun's declination suvers suversed sine Tang tangent of half trigonometric functions values whence yards
Popular passages
Page 4 - The logarithm of any power of a number is equal to the logarithm of the number multiplied by the exponent of the power.
Page 7 - This process, like its converse (Art. 23), is based upon the supposition that the differences of logarithms are proportional to the differences of their corresponding numbers.
Page 4 - The logarithm of any POWER of a number is equal to the product of the logarithm of the number by the exponent of the power. For let m be any number, and take the equation (Art. 9) M=a*, then, raising both sides to the wth power, we have Mm = (a")m = a"" . Therefore, log (M m) = xm = (log M) X »»12.
Page 74 - Spherical Triangle the cosine of any side is equal to the product of the cosines of the other two sides, plus the product of the sines of those sides into the cosine of their included angle ; that is, (1) cos a = cos b...
Page 43 - In every plane triangle, the sum of two sides is to their difference as the tangent of half the sum of the angles opposite those sides is to the tangent of half their difference.
Page 39 - ... be at the head of the column, take the degrees at the top of the table, and the minutes on the left ; but if the name be at the foot of the column, take the degrees at the bottom, and the minutes on the right.
Page 46 - The cosine of half of any angle of a plane triangle is equal to the square root of half the sum of the three sides, into half the sum less the side opposite the angle, divided by the rectangle of the two adjacent sides.