Euclid's Elements of geometry, books i. ii. iii. iv1862 |
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Page 12
... bisect a given rectilineal angle , that is , to divide it into two equal parts . ( References - Prop . I. 1 , 3 , 8. ) Given . - Let BAC be the given rectilineal angle . Sought . It is required to bisect it . Construction . - 1 . Take ...
... bisect a given rectilineal angle , that is , to divide it into two equal parts . ( References - Prop . I. 1 , 3 , 8. ) Given . - Let BAC be the given rectilineal angle . Sought . It is required to bisect it . Construction . - 1 . Take ...
Page 13
... bisected by the straight line AF . Q. E. F. PROPOSITION 10. - PROBLEM . To bisect a given finite straight line , that is , to divide it into two equal parts . ( References - Prop . I. 1 , 4 , 9. ) Given . Let AB be the given straight ...
... bisected by the straight line AF . Q. E. F. PROPOSITION 10. - PROBLEM . To bisect a given finite straight line , that is , to divide it into two equal parts . ( References - Prop . I. 1 , 4 , 9. ) Given . Let AB be the given straight ...
Page 15
... Bisect FG in H. ( I. 10. ) 4. Join CF , CH , CG . H E A F G B D Then CH shall be perpendicular to AB . Proof . - 1 . Because FH is equal to HG ( const . ) , and HC common to the two triangles FHC , GHC ; 2. The two sides FH , HC , are ...
... Bisect FG in H. ( I. 10. ) 4. Join CF , CH , CG . H E A F G B D Then CH shall be perpendicular to AB . Proof . - 1 . Because FH is equal to HG ( const . ) , and HC common to the two triangles FHC , GHC ; 2. The two sides FH , HC , are ...
Page 18
... Bisect AC in E. ( I. 10. ) 2. Join BE , and produce it to F , making EF equal to BE ( I. 3 ) , and B join FC ... bisected , and the side AC he produced to G , it may be proved that the angle BCG ( or its equal ACD ) , is greater ...
... Bisect AC in E. ( I. 10. ) 2. Join BE , and produce it to F , making EF equal to BE ( I. 3 ) , and B join FC ... bisected , and the side AC he produced to G , it may be proved that the angle BCG ( or its equal ACD ) , is greater ...
Page 34
... bisect it . Demonstration . - 1 . Because AB is parallel to CD , and BC meets them , the alternate angles ABC , BCD , are equal to one another . ( I. 29. ) 2. Because AC is parallel to BD , and BC meets them , the alternate angles ACB ...
... bisect it . Demonstration . - 1 . Because AB is parallel to CD , and BC meets them , the alternate angles ABC , BCD , are equal to one another . ( I. 29. ) 2. Because AC is parallel to BD , and BC meets them , the alternate angles ACB ...
Common terms and phrases
AB is equal AC and CB adjacent angles angle ABC angle AGH angle BAC angle BCD angle EAB angle EDF angle equal angles CBA base BC BC is equal bisected circle ABC circumference Conclusion Conclusion.-Therefore const Construction.-1 Demonstration.-1 describe the circle diameter double equal angles equal to CD equiangular exterior angle given circle given point given rectilineal angle given straight line Given.-Let ABCD gnomon greater Hypothesis inscribed interior and opposite isosceles triangle less opposite angle parallel to CD parallelogram perpendicular point F produced Q. E. D. PROPOSITION rectangle AB BC rectangle AE rectangle contained rectilineal figure References-Prop remaining angle required to describe right angles segment semicircle Sequence side BC square on AC straight line AC straight line drawn touches the circle triangle ABC triangle DEF twice the rectangle
Popular passages
Page 25 - If two triangles have two angles of the one equal to two angles of the other, each to each ; and one side equal to one side, viz.
Page 2 - A circle is a plane figure contained by one line, which is called the circumference, and is such that all straight lines drawn from a certain point within the figure to the circumference, are equal to one another.
Page 99 - The angle in a semicircle is a right angle; the angle in a segment greater than a semicircle is less than a right angle; and the angle in a segment less than a semicircle is greater than a right angle.
Page 4 - If a straight line meets two straight lines, so as to " make the two interior angles on the same side of it taken " together less than two right angles...
Page 66 - ... the sides containing the obtuse angle, by twice the rectangle contained by the side upon which, when produced, the perpendicular falls, and the straight line intercepted without the triangle between the perpendicular and the obtuse...
Page 65 - To divide a given straight line into two parts, so that the rectangle contained by the whole, and one of the parts, may be equal to the square of the other part.
Page 32 - F, which is the common vertex of the triangles ; that is, together with four right angles. Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Page 58 - If a straight line be bisected, and produced to any point ; the rectangle contained by the whole line thus produced, and the part of it produced...
Page 88 - The straight line drawn at right angles to the diameter of a circle, from the extremity of it, falls without the circle...
Page 33 - The straight lines which join the extremities of two equal and parallel straight lines towards the same parts, are also themselves equal and parallel.