Now take the latitudes and departures of IC and CN, and by balancing, find the latitude and departure of the division line NI, with which find its bearing and distance. *

Note. It is the corrected latitudes and departures that are to be used throughout the calculation.

EXAMPLES.

1. Let the bearing of AB be N. 19° E. dist. 27 ch. BC, S. 77° E. 22.75 ch. CD, S. 27° E. 28.75 ch. DE, S. 52° W. 14.50 ch. EF, S. 15°; E. 19 ch. FG, West, 17.72 ch. GH, N. 36° W. 11.75 ch. HI, North, 16.07 ch., and IA, N. 62° W. 14.88 ch.; it is required to divide the tract into two equal parts by a line IN running from the corner I and falling on the opposite side CD.

First, calculate the whole

A a

Sta. Courses.

Dist.

N.

AB N. 19°E. 27.00 25.53

BC S. 77 E.

22.75

CD S. 27 E. 28.75

DE S. 52 W. 14.50

EF S. 15 E. 19.00

FG

West, 17.72

GHN. 36 W. 11.75

HI North,

IA N. 62 W. 14.88

(172.42

16.07

9.51

16.07

6.98

58.09
57.98

.11 Er. S.

0 | 4

57.98 49.09 49.19

49.09

.02

11.42.01

01.01

.02 .02

.01

3.01 .01

.01

.0.1 .01

.01

.01

.10 Er. E.

..01

.10 58.04 58.04 49.15 49.15

Area of ABCDEFGHIA (sq. ch.)

Half

do.

(sq. ch.)

110.4583

136.7145

1587.1160

568.2264

1048.6368

.4462

400.8022 3451.5982 400.8022

2)3050.7960

1525.3980

762.6990

To find the latitude and departure of CI, and area of the

part IABCI.

Area of IABCI (sq. ch.)
Half area of ABCDEFGHIA

Area of ICNI

(sq. ch.)

To find the area of ICDI.

E. W. M. Dist. N.area.

0.00 17.85 E

To find the latitude and departure of NI.

Sta N.

IC 27.35

CN

NI

E.

13.55 6.91

As diff. of lat. of NI, 13.80 S. do. 24.76 W.

17.85

(13.80)

27.35 27.35 24.76-24.76

sec. bearing of NI, 60° 52′

:: diff. lat.

do. 13.80

W.

To find the bearing and distance of NI.

: dep.

:: rad.

: tang. bearing of NI, S. 60° 52′ W.

As rad.

24.76

Ar. Co. 0.00000

10.31261

1.13988

1.45249

; dist. NI, 28.35 ch.

Hence IN bears, N. 60° 52′ E. dist. 28.35 ch.

2. Given the boundaries of a tract of land as follow; viz. 1st. S. 35°4 W. 11.20 ch.. 2nd. N. 45° W. 24.36 ch. 3rd. N. 15° E. 10.80 ch. 4th. S. 77 E. 16 ch. 5th. N. 87° E. 21.50 ch. 6th. S. 60° E. 14.80 ch. 7th. South, 10.91 ch. 8th. N. 85° W, 29.28 ch. to the place of beginning; to divide the tract into two equal parts by

1

a line running from the first station and falling on one of the opposite sides: the bearing and distance of the division line are required. Ans. N. 7° 18′ E. 15.28 ch.

VARIATION OF THE COMPASS,

A meridian pointed out by the magnetic needle is not in general a true one; for the needle does not point truly to the north point of the horizon, but varies from it, in some places to the eastward, and in others to the westward.

The angle contained between the true meridian and that pointed out by the needle, is called the variation of the compass.

The variation is named east or west, according as the needle points to the eastward or westward of the true north.

As the variation is different in different places, so also in the same place it does not remain the same, but differs sensibly in the course of a few years. Hence in running a lìne that was run a number of years previously, the bearing will be found different from what it was at that time; this, together with the difference in compasses, causes many difficulties, and frequently inaccuracies, in