IA IB 9.99335 9.80807 1.44716 11.25523 log. 1.26188 To find the double area of the triangle IAB. As rad. 10.00000 : sin. AIB 13° 45' 9.37600 log. 1.46937 :: IAXIB, 1.54943 : 2IAB 248.2 2.39480 To find the double area of the triangle IBC. As rad. 10.00000 : sin. BIC 9° 15' 9.20613 SIB :: IBXIC, log. 1.54943 IC 1.47463 To find the double area of the triangle ICD. As rad. 10.00000 9.52350 log. 1.47463 1.48780 :: IC× ID, sin. CID 19° 30' SIC ID : 2.ICD 306.15 To find the double area of the triangle IDE. As rad. 10.00000 : sin. DIE 26° 30' 9.64953 log. 1.48780 1.34698 :: ID×IE, IE { : 2.IDE 305.007 ID 2.48593 To find the double area of the triangle IEF. As rad. 10.00000 : sin. EIF 24° 00′ 9.60931 :: IE-IF,{ SIE log. 1.34698 IF 1.13542 : 2.IEF 123.511 2.48431 T To find the double area of the triangle IFG. As rad. 10.00000 9.36818 :: IF×IG, { : sin. FIG 13° 30 SIF log. 1.13542 IG 1.26188 : 2.IFG 58.274 2.09171 1.76548 To find the double area of the triangle IAG. As rad. 10.00000 9.71809 log. 1.46937 2.44934 2.IAB sin. AIG 31° 30' :: IA×IG, IG : 2.1AG 281.412 2.IBC 2,1CD 2.IDE 2.IABCDEI 2.IAGFEL® 169.9 306.15 305.007 1029.257 463.197 2.ABCDEFGA 566.060 ABCDEFGA EXAMPLE 2. 2.IFG 58.274 2.IAG 281.412 2.IAGFEI 463.197 283.03 Ch. 28 A. 1 R. 8 P. The bearings and distances of the sides, if required, might readily be obtained. For, having found the distances IA, IB, we have in the triangle IAB, two sides and an included angle; whence the angle IAB and side AB may be found. The angle IAB applied to the bearing of IA, will give the bearing of AB. In the same manner the bearings and distances of the other sides may be found. Being required to calculate the area of a field, the owner of which refuses permission to go on it, I choose all the angles of the field are visible. The bearing and distance of the stations, and the bearings of the angles, from each station, are as follow. What is the area of the field? The station G bears from the station F, N. 43° W. 20 ch. LAYING OUT AND DIVIDING LAND. PROBLEM 1. To lay out a given quantity of land in a square form. Reduce the given quantity to chains or perches and extract the square root, which will be the length of a side, of the same denomination to which the given quantity is reduced. RULE. EXAMPLES. 1. Required the side of a square that shall contain 9 A. 3 R. 28 P. 40)28 Per. 4)3.7 R. 9.925 A. -99.25 Ch. Ch. 99.25(9.96 Ch. the length of a side. 81 189)1825 1701 1986)12400 11916 |