Continuous Symmetry: From Euclid to Klein"This text is for a one-semester undergraduate course on geometry. It is richly illustrated and contains hundreds of exercises."--BOOK JACKET. |
From inside the book
Results 1-5 of 39
Page xi
... formulas to Jordan content for more exotic shapes . The treatment is relatively abbrevi- ated and provides many opportunities for students to fill in the details ( with generous hints ) . Throughout the book the approach is concrete ...
... formulas to Jordan content for more exotic shapes . The treatment is relatively abbrevi- ated and provides many opportunities for students to fill in the details ( with generous hints ) . Throughout the book the approach is concrete ...
Page xiv
... attention the problem of giving formulas for the solutions of polynomial equations . However , he applied his own unique and revolutionary approach to the problem . Galois was too smart for his own good . A xiv Student Preface.
... attention the problem of giving formulas for the solutions of polynomial equations . However , he applied his own unique and revolutionary approach to the problem . Galois was too smart for his own good . A xiv Student Preface.
Page 21
... formulas for coordi- nate systems Xe for each type of Moulton line l , verifying that the distance function on MP2 so produced agrees with the R2 distance in the sense stated above . ( These formulas will not be needed for the other ...
... formulas for coordi- nate systems Xe for each type of Moulton line l , verifying that the distance function on MP2 so produced agrees with the R2 distance in the sense stated above . ( These formulas will not be needed for the other ...
Page 43
You have reached your viewing limit for this book.
You have reached your viewing limit for this book.
Page 106
You have reached your viewing limit for this book.
You have reached your viewing limit for this book.
Contents
XXXVI | 235 |
XXXVII | 240 |
XXXVIII | 251 |
XL | 256 |
XLI | 266 |
XLII | 276 |
XLIII | 287 |
XLIV | 292 |
XIII | 62 |
XIV | 70 |
XV | 84 |
XVI | 94 |
XVII | 110 |
XVIII | 115 |
XIX | 119 |
XX | 121 |
XXI | 135 |
XXII | 146 |
XXIII | 156 |
XXIV | 161 |
XXV | 165 |
XXVII | 181 |
XXVIII | 188 |
XXIX | 191 |
XXX | 199 |
XXXI | 206 |
XXXII | 211 |
XXXIII | 217 |
XXXIV | 224 |
XXXV | 231 |
XLV | 298 |
XLVI | 309 |
XLVII | 315 |
XLVIII | 322 |
XLIX | 340 |
L | 347 |
LII | 356 |
LIII | 363 |
LIV | 375 |
LV | 376 |
LVI | 399 |
LVII | 416 |
LVIII | 439 |
LIX | 459 |
LXI | 467 |
LXII | 482 |
LXIII | 487 |
LXIV | 505 |
LXV | 520 |
LXVI | 531 |
LXVII | 533 |
Other editions - View all
Common terms and phrases
AABC ABCD Axiom circle collinear composition compute congruent conjugacy conjugacy classes conjugate consider containing coordinate system define Definition denote desired dilation factor directed angle measure distance Dp,s equal equilateral equivalent Euclidean geometry example Exercise exists finite fixed point frieze groups frieze pattern glide reflection group G Hence Hint integer interior angles intersect invariant isometry group L-Jordan measurable l₁ lattice line segment maps medial triangle midpoint non-split non-trivial orientation-preserving orientation-reversing orthic triangle parallel lines Parallel Postulate parallelogram perpendicular bisector point group point inversion polygonal regions preserves proof properties Proposition Prove quadrilateral radius real number rectangle result rhombic rotation angle shown in Figure side length split groups square Structure Theorem Suppose symmetry group transformations translation group translation orbit translation subgroup triangle ABC uniform dilation unique verify vertex vertices wallpaper groups y₁
Popular passages
Page xiii - That, if a straight line falling on two straight lines makes the interior angles on the same side less than two right angles, the two straight lines, if produced indefinitely, meet on that side on which are the angles less than the two right angles.
Page 58 - The sum of the lengths of any two sides of a triangle is greater than the length of the third side.
Page 48 - The SAS Postulate: Given a correspondence between two triangles (or between a triangle and itself). If two sides and the included angle of the first triangle are congruent to the corresponding parts of the second triangle, then the correspondence is a congruence.
Page 4 - the best way to explain it is to do it." (And, as you might like to try the thing yourself some winter day, I will tell you how the Dodo managed it.) First it marked out a race-course, in a sort of circle, ("the exact shape doesn't matter," it said,) and then all the party were placed along the course, here and there. There was no "One, two...
Page 61 - If two sides of one triangle are equal to two sides of a second triangle and the included angle of the first is greater than the included angle of the second, then the third side of the first triangle is greater than the third side of the second.
Page 294 - A median of a triangle is a line which joins a vertex of the triangle to the midpoint of the opposite side. Let ABC be any triangle, and let a, b and c be position vectors, of A, B and C relative to some fixed origin.
Page 114 - The radius of a circle is a line segment from the center of the circle to a point on the circle.
Page 48 - If two sides of a triangle are congruent, then the angles opposite these sides are congruent.
Page 68 - The sum of the measures of the interior angles of any triangle is 180°.
Page 120 - Suppose a correspondence between two triangles is such that two sides and the included angle of the first triangle are congruent to the corresponding parts of the second triangle.