Mathematical Exercises ...1864 |
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Page 113
... the solid content of a log of timber 10 yds . 2 ft . 7 in . long , 2 ft . 11 in . broad , and 2 ft . 5 in . thick . 10. If a pressure of 15 lbs . to the square inch be applied to a circular plate 3 ft . in diameter , PAPERS . 113.
... the solid content of a log of timber 10 yds . 2 ft . 7 in . long , 2 ft . 11 in . broad , and 2 ft . 5 in . thick . 10. If a pressure of 15 lbs . to the square inch be applied to a circular plate 3 ft . in diameter , PAPERS . 113.
Page 114
... pressure ? 11. Find the number of cubic feet in a hexagonal room , each side of which is 20 ft . and its height 30 ft .; and which is finished above with a roof in the form of a hexagonal pyramid 15 ft . high . 12. What is the solid ...
... pressure ? 11. Find the number of cubic feet in a hexagonal room , each side of which is 20 ft . and its height 30 ft .; and which is finished above with a roof in the form of a hexagonal pyramid 15 ft . high . 12. What is the solid ...
Page 222
... a system of bodies , x = In the lever , P Σ ( P.X ) Σ ( Ρ ) Σ ( P.y ) : y = Σ ( Ρ ) perpendicular from fulcrum on w's direction W perpendicular from fulcrum on P's direction Pressure on fulcrum = p2 + w2 - 2 PW 222 MIXED MATHEMATICS .
... a system of bodies , x = In the lever , P Σ ( P.X ) Σ ( Ρ ) Σ ( P.y ) : y = Σ ( Ρ ) perpendicular from fulcrum on w's direction W perpendicular from fulcrum on P's direction Pressure on fulcrum = p2 + w2 - 2 PW 222 MIXED MATHEMATICS .
Page 223
Samuel H. Winter. Pressure on fulcrum = p2 + w2 - 2 PW cos ( a + ß ) . Direction of pressure = 0 ; tan 0 = In the wheel and axle Single moveable pulley , the things . P sin a + w sin 3 P cos a - w cos P rad . of axle -- W rad . of wheel ...
Samuel H. Winter. Pressure on fulcrum = p2 + w2 - 2 PW cos ( a + ß ) . Direction of pressure = 0 ; tan 0 = In the wheel and axle Single moveable pulley , the things . P sin a + w sin 3 P cos a - w cos P rad . of axle -- W rad . of wheel ...
Page 224
... FORMULE IN HYDROSTATICS . Normal pressure on area a2 , the depth of whose centre of gravity below surface of fluid is h = weight of volume a h of the fluid . Specific gravity of a substance weight of any volume of 224 FORMULE .
... FORMULE IN HYDROSTATICS . Normal pressure on area a2 , the depth of whose centre of gravity below surface of fluid is h = weight of volume a h of the fluid . Specific gravity of a substance weight of any volume of 224 FORMULE .
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acres angle arithmetical axis ball base binomial theorem bisecting body CALC cent centre of gravity circle coefficient of friction cost cube cubic foot curve cwts cylinder determine diameter Divide drawn ellipse equal equilibrium Express Extract the square feet find the centre Find the distance Find the equation Find the number Find the value fluid forces acting formula geometrical given horizontal plane inches inclined plane inscribed intersect latus rectum length logarithms lowest terms miles an hour Multiply parabola parallel perpendicular places of decimals plane triangle pressure Prove pulleys radius rectangular recurring decimal Reduce right-angled sides simple interest Simplify sin² Solve the equations square root straight line string Sum the series surface tangent theorem tons tower TRIG velocity vertex vertical vulgar fractions weight yards
Popular passages
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Page 150 - ... a gallon he gained 15 per cent. on the price of the wine, and 20 per cent. on the price of the brandy : in what ratio were the wine and brandy mixed together?
Page 255 - If he sell to each of two customers a pound of tea at 2s. 9<7. per pound, putting his weights into different scales for each transaction, find whether he gains or loses owing to the incorrectness of his balance, and how much. 6. Find the ratio of the power to the weight in a system of pulleys, each pulley being suspended by a separate vertical string, which has one end fixed to a beam above. [The weight of the pulleys may be neglected.] 7. Describe the Wheel-and-axle. If the string from the axle...