The Mechanics of Construction, EtcDughton, Bull & Company, 1861 |
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Page 15
... feet long , capable of raising a weight W , including the weight of the pump . If r be the unknown radius of the pump in inches , and w its weight per cubic foot , the whole weight to be raised will be W + π r 2 ( 12 ) * w.l. Hence if S ...
... feet long , capable of raising a weight W , including the weight of the pump . If r be the unknown radius of the pump in inches , and w its weight per cubic foot , the whole weight to be raised will be W + π r 2 ( 12 ) * w.l. Hence if S ...
Page 16
... feet long , and 5 inches in circumference , is suspended from one extremity ; find what force applied vertically at the other extremity would produce fracture , the coefficient of ultimate strength being taken at 27 tons , and the ...
... feet long , and 5 inches in circumference , is suspended from one extremity ; find what force applied vertically at the other extremity would produce fracture , the coefficient of ultimate strength being taken at 27 tons , and the ...
Page 26
... feet . Ans . 74,400 lbs . ( 5. ) A force of 500 lbs . acts on a piston of a forcing pump which communicates pressure to a hollow sphere of 10 inches radius ; find the thickness of metal of the sphere in order that it may sustain the ...
... feet . Ans . 74,400 lbs . ( 5. ) A force of 500 lbs . acts on a piston of a forcing pump which communicates pressure to a hollow sphere of 10 inches radius ; find the thickness of metal of the sphere in order that it may sustain the ...
Page 55
... feet asunder at its extremities , which are in the same horizontal line ; find what weight sus- pended from its centre would produce fracture , the coefficient of fracture being 7850 . The formula of solution is ( Arts . 38 , 40 ) , SI ...
... feet asunder at its extremities , which are in the same horizontal line ; find what weight sus- pended from its centre would produce fracture , the coefficient of fracture being 7850 . The formula of solution is ( Arts . 38 , 40 ) , SI ...
Page 56
... feet asunder , what weight suspended 3 feet from one extremity would produce fracture ? If the beam merely rested on two supports in the same hori- zontal plane , the formula of solution ( Arts . 38 , 40 ) would be , pq • W = SI 1 = X 6 ...
... feet asunder , what weight suspended 3 feet from one extremity would produce fracture ? If the beam merely rested on two supports in the same hori- zontal plane , the formula of solution ( Arts . 38 , 40 ) would be , pq • W = SI 1 = X 6 ...
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Common terms and phrases
angle axle beam breadth c₁ catenary centre of gravity centre of pressure chain circular arch coefficient of resistance coefficient of safety common catenary compression cosec cross section cubic foot curve of pressure cylinder deflection Denote density determined diameter dimensions Edition equal equation equilibrium exterior forces extrados extremity F. A. Paley Fcap feet fibre find the thickness fixed formula fracture h₁ Hence horizontal line horizontal position horizontal thrust inertia intrados king-post length lever arm load lowest point modulus of elasticity moment of inertia moments neutral axis parabola parallel perpendicular plane preceding prism PROP r+ h r₁ radius rafter rectangular roof section HK segmental arch sin² springing line stability straining force supported supposed surcharge thickness of pier tie-beam torsion trapezoid triangle vertical pressure weight Wherefore
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