Books Books To prove that the exterior angle of a triangle is equal to the sum of the two interior opposite angles (see fig. A Course of Mathematics: For the Use of Academies, as Well as Private Tuition - Page 70
by Charles Hutton - 1831 ## A Course of Mathematics: In Three Volumes : Composed for the Use of the ...

Charles Hutton - Mathematics - 1811
...instrument, or the summit of the observed angle APB : it is required to find c, the measure of ACS, supposing there to be known APB = p, BPC = p, CP ==...we have, with respect to the triangle IAP, AIB = P + IAF-, and with regard to the triangle BIC, AIB = c + CBP. Making these two values of AIB. equal,... ## A Course of Mathematics ...: Composed for the Use of the Royal Military ...

Charles Hutton - Mathematics - 1811
...: -it is required to find c, the measure of ACE, supposing there to be • known АРБ = p, UPC = p, CP =: d, BC = L, AC = R. Since the exterior angle...we have, with respect to the triangle IAP, AIB = p -f- IAP ; and with regard to the triangle BIC, AIB = с + СВР. Making thest two values of AIB equal,... ## A Treatise on Surveying, Containing the Theory and Practice: To which is ...

John Gummere - Plane trigonometry - 1814 - 346 pages
...took the angle of elevation BAG = 26° 30'. Required the height of the tree. Calculation. 1. Because the exterior angle of a triangle is equal to the sum of the two interior and opposite ones, the angle BDC = DAC + ACD ; therefore ACD - BDC — DAG = 25° : now in the triangle... ## Elements of Plane and Spherical Trigonometry: With Their Applications to ...

Olinthus Gregory - Plane trigonometry - 1816 - 244 pages
...staof the centre of 'r the sutnmit of ;Ie APB : it is re* the measure of here to be known p, ce = d,BQ Since the exterior angle of a triangle is equal to the sum of the two interior opposite angles, we have, with respect to the triangle IAP, AIB = P + IAP; and with regard to the triangle BIC, AIB... ## An Elementary Treatise on the Application of Trigonometry: To Orthographic ...

John Farrar - Logarithms - 1822 - 153 pages
...another distance CB = 60 feet in the same direction, and take the angle ABD = 23° 45'. Now, sinre the exterior angle of a triangle is equal to the sum of the interior opposite angles, we have that is 4l° — 23° 45' =17° 15'. Hence in the triangle BAC.... ## An Elementary Treatise on the Application of Trigonomentry to Orthographic ...

John Farrar - Trigonometry - 1833 - 155 pages
...measure another distance CB = 60 feet in the same direction, and take the angle ABD = 23° 45'. Now, since the exterior angle of a triangle is equal to the sum of the interior opposite angles, we have ACD — A&b = BAC. that is 41° — 23° 45' = 17° 15'. Hence... ## An Elementary Treatise on the Application of Trigonomentry to Orthographic ...

John Farrar - Trigonometry - 1833 - 155 pages
...measure another distance CB = 60 feet in the same direction, and take the angle ABD = 23° 45'. Now, since the exterior angle of a triangle is equal to the sum of the interior opposite angles, we have ACD — ABC = EAC. that is 41° — 23° 45' = 17° 15'. Hence... ## The Schoolmaster: Essays on Practical Education, Selected from the ..., Volume 1

Education - 1836
...example, suppose it known that the angles at the base of an isosceles triangle are equal, and also that the exterior angle of a triangle is equal to the sum of the interior and opposite angles. Suppose it also indisputable, that if A and B be respectively double... ## The schoolmaster: essays on practical education, selected from the works of ...

Schoolmaster - 1836
...example, suppose it known that the angles at the base ofan isosceles triangle are equal, and also that the exterior angle of a triangle is equal to the sum of the interior and opposite angles. Suppose it also indisputable, that if A and B he respectively double... 