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" To prove that the exterior angle of a triangle is equal to the sum of the two interior opposite angles (see fig. "
A Course of Mathematics: For the Use of Academies, as Well as Private Tuition - Page 70
by Charles Hutton - 1831
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A Course of Mathematics: In Three Volumes : Composed for the Use of the ...

Charles Hutton - Mathematics - 1811
...instrument, or the summit of the observed angle APB : it is required to find c, the measure of ACS, supposing there to be known APB = p, BPC = p, CP ==...we have, with respect to the triangle IAP, AIB = P + IAF-, and with regard to the triangle BIC, AIB = c + CBP. Making these two values of AIB. equal,...
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A Course of Mathematics ...: Composed for the Use of the Royal Military ...

Charles Hutton - Mathematics - 1811
...: -it is required to find c, the measure of ACE, supposing there to be • known АРБ = p, UPC = p, CP =: d, BC = L, AC = R. Since the exterior angle...we have, with respect to the triangle IAP, AIB = p -f- IAP ; and with regard to the triangle BIC, AIB = с + СВР. Making thest two values of AIB equal,...
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A Treatise on Surveying, Containing the Theory and Practice: To which is ...

John Gummere - Plane trigonometry - 1814 - 346 pages
...took the angle of elevation BAG = 26 30'. Required the height of the tree. Calculation. 1. Because the exterior angle of a triangle is equal to the sum of the two interior and opposite ones, the angle BDC = DAC + ACD ; therefore ACD - BDC — DAG = 25 : now in the triangle...
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Elements of Plane and Spherical Trigonometry: With Their Applications to ...

Olinthus Gregory - Plane trigonometry - 1816 - 244 pages
...staof the centre of 'r the sutnmit of ;Ie APB : it is re* the measure of here to be known p, ce = d,BQ Since the exterior angle of a triangle is equal to the sum of the two interior opposite angles, we have, with respect to the triangle IAP, AIB = P + IAP; and with regard to the triangle BIC, AIB...
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An Elementary Treatise on the Application of Trigonometry: To Orthographic ...

John Farrar - Logarithms - 1822 - 153 pages
...another distance CB = 60 feet in the same direction, and take the angle ABD = 23 45'. Now, sinre the exterior angle of a triangle is equal to the sum of the interior opposite angles, we have that is 4l — 23 45' =17 15'. Hence in the triangle BAC....
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An Elementary Treatise on the Application of Trigonomentry to Orthographic ...

John Farrar - Trigonometry - 1833 - 155 pages
...measure another distance CB = 60 feet in the same direction, and take the angle ABD = 23 45'. Now, since the exterior angle of a triangle is equal to the sum of the interior opposite angles, we have ACD — A&b = BAC. that is 41 — 23 45' = 17 15'. Hence...
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An Elementary Treatise on the Application of Trigonomentry to Orthographic ...

John Farrar - Trigonometry - 1833 - 155 pages
...measure another distance CB = 60 feet in the same direction, and take the angle ABD = 23 45'. Now, since the exterior angle of a triangle is equal to the sum of the interior opposite angles, we have ACD — ABC = EAC. that is 41 — 23 45' = 17 15'. Hence...
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The Schoolmaster: Essays on Practical Education, Selected from the ..., Volume 1

Education - 1836
...example, suppose it known that the angles at the base of an isosceles triangle are equal, and also that the exterior angle of a triangle is equal to the sum of the interior and opposite angles. Suppose it also indisputable, that if A and B be respectively double...
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The schoolmaster: essays on practical education, selected from the works of ...

Schoolmaster - 1836
...example, suppose it known that the angles at the base ofan isosceles triangle are equal, and also that the exterior angle of a triangle is equal to the sum of the interior and opposite angles. Suppose it also indisputable, that if A and B he respectively double...
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A system of practical mathematics; being no.xvi. of a new series of school-books

Scottish school-book assoc - 1845
...required to find C, the measure of ACB, supposing there to be known APB=P, BPC= p, CP=d, BC=L, AC=R. Since the exterior angle of a triangle is equal to the sum of the two interior opposite angles, (Geo. prop. ] 9), we have, with respect to the triangle IAP, ZAIB=ZP+UAP ; and with regard to the triangle...
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