Euclid's Elements of geometry, the first three books (the fourth, fifth, and sixth books) tr. from the Lat. To which is added, A compendium of algebra (A compendium of trigonometry).1846 |
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... constructed on the parts of any divided line , & c . The Third Book treats of the properties of the circle . With paying attention , and not stepping forward too quickly , until all going before is established in the mind , students ...
... constructed on the parts of any divided line , & c . The Third Book treats of the properties of the circle . With paying attention , and not stepping forward too quickly , until all going before is established in the mind , students ...
Page 7
... constructed upon the given right line AB ; but it is equilateral ; for AC is equal to AB , because they are the ... construct an equilateral triangle ADB ( by Prop . 1 ) . From the centre B , with the interval BC , describe a circle ...
... constructed upon the given right line AB ; but it is equilateral ; for AC is equal to AB , because they are the ... construct an equilateral triangle ADB ( by Prop . 1 ) . From the centre B , with the interval BC , describe a circle ...
Page 8
... constructed . PROPOSITION III . PROBLEM . From the greater of two given right lines ( AB and CF ) to cut off a part equal to the less . From either extremity A of the greater right line , draw AD , equal to the less CF of the given ...
... constructed . PROPOSITION III . PROBLEM . From the greater of two given right lines ( AB and CF ) to cut off a part equal to the less . From either extremity A of the greater right line , draw AD , equal to the less CF of the given ...
Page 10
... . Upon the same right line ( AB ) and on the same side of it , there cannot be constructed two triangles ( ACB , ADB ) whose conterminous sides ( AC and AD , BC and BD ) can be equal . For , if it be possible , let them be 10 FIRST BOOK .
... . Upon the same right line ( AB ) and on the same side of it , there cannot be constructed two triangles ( ACB , ADB ) whose conterminous sides ( AC and AD , BC and BD ) can be equal . For , if it be possible , let them be 10 FIRST BOOK .
Page 11
... constructed on the same right line cannot have their conterminous sides equal , if the vertex of each fall without the other . F Now let the vertex D of either fall within the other ; and draw CD produce AC and AD to E and F. Since in ...
... constructed on the same right line cannot have their conterminous sides equal , if the vertex of each fall without the other . F Now let the vertex D of either fall within the other ; and draw CD produce AC and AD to E and F. Since in ...
Common terms and phrases
absurd AC and CB AC by Prop AC is equal angle ABC angle equal angles by Prop arch bisected centre circumference co-efficient Const construct contained oftener diameter divided divisor double equal angles equal by Constr equal by Hypoth equal by Prop equal right lines equal to AC equal to twice equi-multiples equi-submultiples equiangular equilateral external angle fore fraction given angle given circle given line given right line given triangle greater half a right inscribed less multiplied opposite parallel parallelogram perpendicular PROPOSITION quantities quotient ratio rectangle under AC remaining angles remaining side right angle right line AB right line AC SCHOL segment semicircle side AC similar similarly demonstrated squares of AC submultiple subtract THEOREM tiple touches the circle triangle BAC twice the rectangle twice the square whole
Popular passages
Page 20 - If two triangles have two sides of the one equal to two sides of the...
Page 30 - DE : but equal triangles on the same base and on the same side of it, are between the same parallels ; (i.
Page 209 - ... they have an angle of one equal to an angle of the other and the including sides are proportional; (c) their sides are respectively proportional.
Page 218 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Page 114 - To reduce fractions of different denominators to equivalent fractions having a common denominator. RULE.! Multiply each numerator into all the denominators except its own for a new numerator, and all the denominators together for a common denominator.
Page 90 - The angle in a semicircle is a right angle ; the angle in a segment greater than a semicircle is less than a right angle ; and the angle in a segment less than a semicircle is greater than a right angle.
Page 129 - In any proportion, the product of the means is equal to the product of the extremes.
Page 163 - Magnitudes are said to be in the same ratio, the first to the second and the third to the fourth, when, if any equimultiples whatever be taken of the first and third, and any equimultiples whatever of the second and fourth, the former equimultiples alike exceed, are alike equal to, or alike fall short of, the latter equimultiples respectively taken in corresponding order.
Page 215 - ... are to one another in the duplicate ratio of their homologous sides.
Page 160 - PROPOSITION XV. PROBLEM. To inscribe an equilateral and equiangular hexagon in a given circle. Let ABCDEF be the given circle.