Elements of Geometry: With Notes |
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Page 5
... . 7. The whole is equal to the sum of the parts into which it is divided . POSTULATES . 1. Grant that a straight line may be drawn from one point to another . 2. And that it may be either increased till it AXIOMS-POSTULATES. ...
... . 7. The whole is equal to the sum of the parts into which it is divided . POSTULATES . 1. Grant that a straight line may be drawn from one point to another . 2. And that it may be either increased till it AXIOMS-POSTULATES. ...
Page 7
... drawn . Let BD be perpendicular to the straight line AB , or AC , BC being the production of AB , and if the truth of the theorem be denied , let some other line , as BE drawn from the same point B , be also perpendicular to AC . Then ...
... drawn . Let BD be perpendicular to the straight line AB , or AC , BC being the production of AB , and if the truth of the theorem be denied , let some other line , as BE drawn from the same point B , be also perpendicular to AC . Then ...
Page 8
... drawn on the same side of another straight line from any point in it , is equal to two right angles ; for , be these angles ever so numerous , they are evidently only subdivisions of the two right angles , which a perpendicular from the ...
... drawn on the same side of another straight line from any point in it , is equal to two right angles ; for , be these angles ever so numerous , they are evidently only subdivisions of the two right angles , which a perpendicular from the ...
Page 9
... drawn through these points , this line and the former will have two points common , they must , there- fore , coincide . PROPOSITION VI . THEOREM . If two straight lines intersect each other , the opposite angles formed at their ...
... drawn through these points , this line and the former will have two points common , they must , there- fore , coincide . PROPOSITION VI . THEOREM . If two straight lines intersect each other , the opposite angles formed at their ...
Page 13
... draw E B M C IK , making MK equal to IM , and join CK . Then the triangles IMB , KMC have the two sides IM , MB , and the included angle in the one equal re- spectively to the two sides KM , MC , and the included angle in the other ...
... draw E B M C IK , making MK equal to IM , and join CK . Then the triangles IMB , KMC have the two sides IM , MB , and the included angle in the one equal re- spectively to the two sides KM , MC , and the included angle in the other ...
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Common terms and phrases
ABCD adjacent angles altitude angle ABC angle ACB angle BAC antecedent base centre chord circ circle circumference circumscribed polygon coincide consequently Prop construction Converse of Prop corollary demonstration described diagonals diameter divided draw enveloping line equal angles equal Prop equimultiples equivalent Euclid exterior angle follows four right angles geometry gonal greater half hence homologous sides hypothenuse hypothesis included angle inscribed angle inscribed polygon intersect isosceles triangle join Legendre less line drawn lines be drawn magnitudes meet multiple number of sides obtuse opposite angles parallel perimeter perpendicular PROBLEM proportion PROPOSITION XII quadrilateral radii rectangle rectangle contained regular polygon respectively equal rhomboid right angled triangle Scholium shorter side BC similar polygons similar triangles submultiple subtended surface tangent THEOREM three angles tiple triangle ABC vertex VIII
Popular passages
Page 159 - ... if a straight line, &c. QED PROPOSITION 29. — Theorem. If a straight line fall upon two parallel straight lines, it makes the alternate angles equal to one another ; and the exterior angle equal to the interior and opposite upon the same side ; and likewise the two interior angles upon the same side together equal to two right angles.
Page 24 - If there be two straight lines, one of which is divided into any number of parts, the rectangle contained by the two straight lines is equal to the rectangles contained by the undivided line, and the several parts of the divided line. Let...
Page 80 - IF a straight line be drawn parallel to one of the sides of a triangle, it shall cut the other sides, or those produced, proportionally; and if the sides, or the sides produced, be cut proportionally, the straight line which joins the points of section shall be parallel to the remaining side of the triangle...
Page 179 - FBC ; and because the two sides AB, BD are equal to the two FB, BC, each to each, and the angle DBA equal to the angle FBC ; therefore the base AD is equal to the base FC, and the triangle ABD to the triangle FBC.
Page 136 - To describe an isosceles triangle, having each of the angles at the base double of the third angle.
Page 179 - BK, it is demonstrated that the parallelogram CL is equal to the square HC. Therefore the whole square BDEC is equal to the two squares GB, HC ; and the square BDEC is described upon the straight line BC, and the squares GB, HC upon BA, AC.
Page 99 - And since a radius drawn to the point of contact is perpendicular to the tangent, it follows that the angle included by two tangents, drawn from the same point, is bisected by a line drawn from the centre of the circle to that point ; for this line forms the hypotenuse common to two equal right angled triangles. PROP. XXXVII. THEOR. If from a point without a circle there be drawn two straight lines, one of which cuts the circle, and the other meets it ; if the rectangle...
Page 29 - In any triangle, the square of a side opposite an acute angle is equal to the sum of the squares of the other two sides diminished by twice the product of one of those sides and the projection of the other side upon it.
Page 179 - FC, and the triangle ABD to the triangle FBC. Now the parallelogram BL is double...
Page 165 - This formula already proves, that if two angles of one triangle are equal to two angles of another, the third angle of the former must also be equal to the third of the latter ; and this granted, it is easy to arrive at the theorem we have in view.