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multiplying this equation by 12, the least common multiple of 2, 3, and 4,

174-6y-6z+4y+3z=120,

and by transposition, 2y+3z=54;

in which, substituting the value of y found above,

2(33-22)+32=54;

or 66-4z+32=54;

... by transposition, z=12;

whence y=33-22-33-24-9,

and x 29-y-z-29-9-12=8.

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It may be observed, that there will be the same variety of solution, as in the last case, according as x, y, or z, is exterminated.

THIRD METHOD.

The values of x, found in each of the equations, being compared, will furnish two equations each involving only y and z; from which the values of y and z may be deduced by any of the rules in the preceding section, and hence, the value of x, can be readily ascertained.

The same observation applies to this method of solution, as did to the last.

In some particular equations, two unknown quantities may be eliminated at once.

Ex. 2. Given x+y+2=31

x+y-z=25

x-y-z-9

to find the values

of x, y, and z.

Adding the first and third equations, 2x=40;

...x=20.

Subtracting the second from the first, 2z=6;

and subtracting the third from the second,

•*. z=3;

2y=16;.. y=8.

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Ex. 3. Given

x-y=2,

x-z=3, to find x, y, and z. y-z=1,

Here, subtracting the first equation from the second, we have y-z=1; which is identically the third.

Therefore, the third equation furnishes no new condition; but what is already contained in the other two; and, consequently, the proposed equations are indeterminate; or, what is the same, we may obtain an infinite number of values which will satisfy the conditions proposed.

This can be easily verified, by comparing the proposed equations with those of (Art. 207), and substituting in the formulæ of roots, (Art. 215); for,

0

0

then we shall find x= y= and z=

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0

0

254. It is proper to remark, that in particular cases, Analysts make use of various other methods, besides those pointed out in the practical rules; in the resolution of equations, which greatly facilitate the calculation, and by means of which, some equations of a degree superior to the first, may be easily resolved, after the same manner as simple equations.

We shall illustrate a few of those artifices, by the following examples.

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and +

1

-=

y

1

1

1

-

2

1

-

to find the values of x, y, and z.

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+-+
OC y 2 720

From this subtracting each of the three first equations, and we shall have

1 31

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-

or z=

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; ..z=23

;

31

31

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u=x-14,

By adding to each member of the first equation, y to the second, and z to the third, we shall

get

x+y+z+u=3x=4y=52;

and from thence, z=, and y= 3x

5

3x

;

4

which values being substituted in the first equation,

we have

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but, by the fourth equation, u=x-14;

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Ex. 6. Given 4x-4y-4z=24, to find the values

6y-2x-2z=24,

and 7z-y-x=24,

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By putting x+y+2=S, the proposed equations

become

8x-4S-24, 8y-25=24, 8z-S=24;

• x=3+1S, y=3+1S, z=3+1S.

By adding these three equations, we have

x+y+z=9+7S; whence S=72. Substituting this value for S, in x, y, and z, we

shall find

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and 2x-4x+40=10, and z.
Ans. x 35, y=30, and z=25.

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Ex. 9. It is required to find the values of x, Y, and 2, in the following equations :

x+y=13, x+2=14, and y+z=15.

Ans. x=6, y=7, and z=8.

Ex. 10. In the following it is required to find the

values of x, y,

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and z.

124,

y z =94,

4 5

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4 5

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Ex. 11. Given x+y+z=26,

to find the va

=4,

lues of x, y, and

x-y
and x-z = 6,
Ans. x=12,

Ex. 12. Given x+y+ z= 9,

x+2y+3z=16,

and xy-2z= 3,

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and z.

Ans. x=4, y=3, and z=2.

Ex. 13. Given x+y+ z=12,) to find the

x+2y+3z=20,

and }x+¦y+ 2= 6,

values of x,

y, and z.

Ans. x=6, y=4, and z=2.

Ex. 14. Given x+y-z=3, x+z-y=9, and y+z-x=10; to find the values of x, y, and z. Ans. x=8, y=9, and z=9.

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Ex. 15. Given x+y=100, y+}z=100, and +=100; to find the values of x, y, and z. Ans. x=64, y=72, and z=84.

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9x+5y-2z 2x+y-3z_7h+2+3

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and

1

+

11

6'

3x+2y+7

6

5y+3z_2x+3y2+22=y—1+2

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to find the values of x, y, and z.

Ans. x=9, y=7, and z=3.

Ex. 17. Given x+y=357, y=3z=476, x+u 595, and u+3x=714; to find the values of x, y, z, and u.

Ans. x=190, y=334, z=426, and u=676;

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