RULE I. When the unknown quantity is only connected with known quantities by the signs plus or minus. 195. Transpose the known quantities to one side of the equation, so that the unknown may stand by itself on the other; and then the unknown quantity becomes known. Ex. 1. Given x+8=9, to find the value of x. By transposition, x=9—8, ., x=1, Ex. 2. Given 3x – 1=2x+5, to find the value By transposition, 3x – 2x=5+4, .. x=9. Ex, 3. Given x ta=a +5, to find the value of x. By taking a from both sides, we have x=5; or by transposition, x=a-at5; but a-a=0, .. x=5, Ex. Given 9-x=2, to find the value of x. By changing the signs of all the terms, we have -9+x=-2, by transposition, x=9-2, .. x=7. It may be remarked, that it is the general praetice of Analysts, to make the unknown quantity appear on the left-hand side of the equation, which is principally the reason for changing the signs. Ex. 5. Given b-x=a-c, to find x in terms of ll, b, and c. (186. Cor. 1), by changing the signs of all the terms, we have b+x=c-a; .. by transposition, x=(-b-a. Ex. 6. Given 2x −4+7=3x - 2, to find the value of . (186.) by transposition, 2x - 3=4-7--2, and (186. Cor. 1), by changing the signs, 3x – 2x=7+ 2-4; but 3x-2c=x, and 7+2-4=5; ..x=5. of s. of x. Ex. 7. Given 7x+3-5=6x-2+7, to find the value of x. Ans. x=7. Ex. 8. Given 3x+5-2-22-7=0, to find the value of x. Ans. x=4. Ex. 9. Given x-3+4-6=0, to find the value Ans. x=5. Ex. 10. Given 7+x=2x+12, to find the value Ans. r=-5. Ex. 11. Given 12-3x=9-2x, to find the value Ans. x=3. Ex. 12. Given x-atb-c=0, to find the value of x in terms of a, b, and c. Ans. x=d-bte. Ex. 13. Given x-a+b=2x- 2a+b, to find the value of a in terms of a and b. Ans. t=a. Ex. 14. Given 2x +a=r+b, to find x in terms of a and b. Ans. x=b-a. RULE II. of x. 196. Transpose the known quantities to one side of the equation, and the unknown to the other, as in the last Rule; then, if the unknown quantity has a coefficient, its value may be found by dividing each side of the equation by the coefficient, or by the sum of the coefficients. Ex. 1. Given 3x +9=18, to find the value of x. By transposition, 3x=13-9, or 3x=9; dividing both sides of the equation by 3, the coefficient of 3x 9 .. =3. 3 3 Ex. 2. Given 20--3=9-*, to find the value , we have of c. By transposition, 2x+x=9+3, by collecting the terms, 3x=12, by division, .. x4. 3 3 Ex. 3. Given 7-4x=3x - 7, to find the value of is. By transposition, - 4x -3x = -7--7, by collecting the terms, — 7x=-14, by changing the signs, 7x=14, 70 14 by division, 7 ; .. x=2. 7 Ex. 4. Given 6x +10=3x +22, to find the value of s. ar C a a By transposition, 6x - 3x =22-10, by collecting the terms, 3x=12, 3x 12 by division, ; x=-4. 3 3 Ex. 5. Given ax+b=c, to find the value of in terms of a, b, and c. By transposition, ax=c--b, Cby division, ; .. x The value of x is equal to cấb divided by a, which may be positive or negative, according as c is greater or less than b; thus, if c=9, b=5, a=2, 9-5 then x= =2; if c=12, b=16, and a=2, then ; 2 12-16 -4 -2. 2 2 Ex. 6. Given 3x-4=72-16, to find the value Ans. x= -3. Ex. 7. Given 9-2x=3x-6, to find the value Ans. x=3. Ex. 8. Given ax + bx=9x2 +cx, to find the value -b of x in terms of a, b, &c. Ans. x= -9 Ex. 9. Given x-9=4x, to find the value of x. Ans. x= of x. of x. a 3 of x. Ex. 10. Given 50x --c=b-3ax, to find the value btc of x in terms of a, b, and c. Ans. x= 80 Ex. 11. Given 3-1 +9-5x=0, to find the value of x. Ans. x=2. Ex. 12. Given ax=ab_ ac, to find the value Ans. x=b-c. Ex. 13. Given x2 + 2x=(x+a), to find the va a Jue of x. Ans. x= 2- 2a Ex. 14. Given (x-1)=x+1, to find the value Ans. x=3. Ex. 15. Given 3+2x+x=(x2 + 3x) x(x - 1) +16, to find the value of x. Ans. x=4. of c. RULE III. 197. If in the equation there be any irreducible fractions, in which the unknown quantity is concerned, multiply every term of the equation by the denominators of the fractions in succession, or by their least common multiple; and then proceed according to Rules I. and Il. 2x Ex. 1. Given +1=x-9, to find the value of x. Multiplying by 4, 2x +4=4x-36, by transposition, 2x --4x=-36-4, by collecting the terms, – 2x=-40, by changing the signs, 2x=40, 40 by division, = 20. 2 2 Ex. 2. Given +35 to find the value X 3 of x. 3 . 2x 2x Multiplying by 2, x — +6=10 4' 63 by 3, 3x - 2x +18=30– 4' by 4, 12x - 3x +72=120-6x, liy transposing, and collecting, 10x=48, 10x 48 by division, .. x=45. 10 10 Or, it is more concise and simple to multiply the equation by the least common multiple of the denominators; because, then the equation is reduced to its lowest terms; thus, Multiplying by 12, the least common multiple of 2, 3, and 4, we have, 6x-4x+36=60-3x, by transposition, 5x=24, 5x 24 by division, 5 i s'ex=49. 5 2 Ex. 3. Given x 1 + to find the value 3 6' of a. Here 30 is the least common multiple of 3, 5, and 6; 30x 30x 30x Multiplying by 30, 30x - -303 + 3 5 6 .. 30x — 10x - 30=6x+5x, by transposition, 9x=30, Эх 30 10 by division, ; ..X=31 9 9 3 Ex. 4. Given -3, to find the value of x. 4 Here 20, the product of 4 and 5, being their least common multiple, |