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Page 66

It remains now to compose R ' with a ' , which is applied in G , to have the

point of application cannot be situated out of IG ; it was then absurd to suppose it

in K . n ...

It remains now to compose R ' with a ' , which is applied in G , to have the

**resultant**of Pand Q . Now it follows , from what has been demonstrated , that thepoint of application cannot be situated out of IG ; it was then absurd to suppose it

in K . n ...

Page 67

We prove that the

the point F , by representing Q by nam ' , and reasoning as above . 2 . ON THE

COMPOSITION OF FORCFS , THE DIRECTIONS OF WHICH FORM ANY ANGLE

...

We prove that the

**resultant**R , of P and Q , cannot be situated on the other side ofthe point F , by representing Q by nam ' , and reasoning as above . 2 . ON THE

COMPOSITION OF FORCFS , THE DIRECTIONS OF WHICH FORM ANY ANGLE

...

Page 68

... we have then = - = tan ' u ; from whence P = Q x tau . a These equations serve

to determine the quantity and direction of the

right - angled triangle A HK , which has for its sides about the right angle , AH = Q

...

... we have then = - = tan ' u ; from whence P = Q x tau . a These equations serve

to determine the quantity and direction of the

**resultant**R . If therefore we form aright - angled triangle A HK , which has for its sides about the right angle , AH = Q

...

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