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Page 66
It remains now to compose R ' with a ' , which is applied in G , to have the
resultant of Pand Q . Now it follows , from what has been demonstrated , that the
point of application cannot be situated out of IG ; it was then absurd to suppose it
in K . n ...
It remains now to compose R ' with a ' , which is applied in G , to have the
resultant of Pand Q . Now it follows , from what has been demonstrated , that the
point of application cannot be situated out of IG ; it was then absurd to suppose it
in K . n ...
Page 67
We prove that the resultant R , of P and Q , cannot be situated on the other side of
the point F , by representing Q by nam ' , and reasoning as above . 2 . ON THE
COMPOSITION OF FORCFS , THE DIRECTIONS OF WHICH FORM ANY ANGLE
...
We prove that the resultant R , of P and Q , cannot be situated on the other side of
the point F , by representing Q by nam ' , and reasoning as above . 2 . ON THE
COMPOSITION OF FORCFS , THE DIRECTIONS OF WHICH FORM ANY ANGLE
...
Page 68
... we have then = - = tan ' u ; from whence P = Q x tau . a These equations serve
to determine the quantity and direction of the resultant R . If therefore we form a
right - angled triangle A HK , which has for its sides about the right angle , AH = Q
...
... we have then = - = tan ' u ; from whence P = Q x tau . a These equations serve
to determine the quantity and direction of the resultant R . If therefore we form a
right - angled triangle A HK , which has for its sides about the right angle , AH = Q
...
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