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Page 202

...

10: 33.137 square chains, or 3a. lr. \0\p. 202 MISCELLANEOUS

CORRESPONDENCE.

...

**inscribed circle**is 1.20710678; but in the present case the radius of the**inscribed circle**is = ^/ 10, therefore by similar areas ( 1.207 10678)': 4.8284271 i:10: 33.137 square chains, or 3a. lr. \0\p. 202 MISCELLANEOUS

CORRESPONDENCE.

Page 203

R. Willerton, W. Proctor, R. Fisher, and J. Clark, Fleet, First 40 = 6,3246 = A G and

£ A G = A B = 3.1623 = the radius of the

= AC, and AC— K DC = AD = ED = DF= 1.3098; therefore, EF = 2 AD = 2-61 96, ...

R. Willerton, W. Proctor, R. Fisher, and J. Clark, Fleet, First 40 = 6,3246 = A G and

£ A G = A B = 3.1623 = the radius of the

**inscribed circle**=CD. Also ^ ~ — 4.4721= AC, and AC— K DC = AD = ED = DF= 1.3098; therefore, EF = 2 AD = 2-61 96, ...

Page 210

... of the segments of the base, and angle NFC the difference of the adjacent

angles are given, HF the diameter of the circumscribing circle is given also. Let L

be the point of contact of the

Geom.

... of the segments of the base, and angle NFC the difference of the adjacent

angles are given, HF the diameter of the circumscribing circle is given also. Let L

be the point of contact of the

**inscribed circle**, then (by proposition 10, ModernGeom.

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