A Course of Mathematics, Volume 2Longman Rees, 1837 - Mathematics |
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Page 2
... drawn from B , perpendicularly to LM , and produced till DM = BM : join AD , and from the point C where AD cuts LM draw BC : also from any other point C ' , assumed in LM , draw C'A , C'B , C'D . Then the triangles DMC , BMC , having ...
... drawn from B , perpendicularly to LM , and produced till DM = BM : join AD , and from the point C where AD cuts LM draw BC : also from any other point C ' , assumed in LM , draw C'A , C'B , C'D . Then the triangles DMC , BMC , having ...
Page 3
... Draw C'D through D , parallel to AB , to cut CE ( drawn perpendicular to AB ) in C ' : then it is to be demonstrated that CE is greater than C ́E . E D The triangles ACB , ADB , are equal both in base and altitude ; but the triangle AC ...
... Draw C'D through D , parallel to AB , to cut CE ( drawn perpendicular to AB ) in C ' : then it is to be demonstrated that CE is greater than C ́E . E D The triangles ACB , ADB , are equal both in base and altitude ; but the triangle AC ...
Page 5
... drawn from the several vertices of the figure to the extremities of the unknown line , are not right angles , or do not ... Draw the diameter EP ; join AP , E D PB ; upon ab = AB make the triangle abp , equal in all respects to ABP ; and ...
... drawn from the several vertices of the figure to the extremities of the unknown line , are not right angles , or do not ... Draw the diameter EP ; join AP , E D PB ; upon ab = AB make the triangle abp , equal in all respects to ABP ; and ...
Page 12
... draw the radius CD to the point of contact of the B D A ! semicircle and VT . Then , because the triangles VAT , VDC , are similar , it is AT : VT :: CD : VC . And , by compos . AT : AT + VT :: CD : CD + CV Therefore VA ; AT : ( AT + VT ) ...
... draw the radius CD to the point of contact of the B D A ! semicircle and VT . Then , because the triangles VAT , VDC , are similar , it is AT : VT :: CD : VC . And , by compos . AT : AT + VT :: CD : CD + CV Therefore VA ; AT : ( AT + VT ) ...
Page 50
... draw , from any point assumed on the surface of the sphere , an arc of a circle which may measure the shortest distance from that point , to the circumference of any given circle ; this arc must be so described , that its prolongation ...
... draw , from any point assumed on the surface of the sphere , an arc of a circle which may measure the shortest distance from that point , to the circumference of any given circle ; this arc must be so described , that its prolongation ...
Other editions - View all
A Course of Mathematics: For the Use of Academies ... as Well as Private Tuition Charles Hutton No preview available - 2015 |
A Course of Mathematics: For the Use of Academies ... As Well As Private Tuition Charles Hutton No preview available - 2022 |
A Course of Mathematics: For the Use of Academies, as Well as Private Tuition Charles Hutton No preview available - 2015 |
Common terms and phrases
abscisses altitude asymptotes Ax² axis ball base becomes bisected body Ca² centre of gravity chord circle circumscribed co-ordinates coefficients cone conic section conjugate conjugate hyperbolas consequently Corol cosec cosine curve denoted determine diameter difference differential direction distance divided draw drawn ellipse equal equation equilibrium expression feet figure find the fluent fluid fluxion force function Geom given Hence horizontal hyperbola inches intersection length logarithm motion ordinate parabola parallel parallelogram pendulum perpendicular plane polygon pressure produced PROP proportional quantity radius ratio rectangle respectively right angles SCHOLIUM sides similar triangles sine solid angles specific gravity sphere spherical triangle square Suppose surface tangent theor theorem transverse trigonometrical variable velocity vertex vertical weight whence