A Course of Mathematics: Composed for the Use of the Royal Military Academy

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William Tegg, 1860 - Mathematics - 895 pages

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Page 334 - EC, have also the same altitude ; and because triangles of the same altitude are to each other as their bases, therefore the triangle ADE : BDE : : AD : DB, and triangle ADE : CDE : : AE : EC.
Page 350 - angle in a segment' is the angle contained by two straight lines drawn from any point in the circumference of the segment, to the extremities of the straight line which is the base of the segment.
Page 328 - Proportion, when the ratio is the same between every two adjacent terms, viz. when the first is to the second, as the second to the third, as the third to the fourth, as the fourth to the fifth, and so on, all in the same common ratio.
Page 25 - OF TIME. 60 Seconds = 1 Minute. 60 Minutes = 1 Hour. 24 Hours = 1 Day. 7 Days = 1 Week. 28 Days = 1 Lunar Month.
Page 340 - CD. conseconsequently the whole polygon, or all the triangles added together which compose it, is equal to the- rectangle of the common altitude CD, and the halves of all the sides, or the half perimeter of the polygon. Now, conceive the number of sides of the polygon to be indefinitely increased ; then will its perimeter coincide with the circumference of the circle, and consequently the altitude CD will become equal to the radius, and the whole polygon equal to the circle. Consequently the space...
Page 299 - The Height or Altitude of a figure is a perpendicular let fall from an angle, or its vertex, to the opposite side, called the base.
Page 34 - Multiply the number in the lowest denomination by the multiplier, and find how many units of the next higher denomination are contained in the product, setting down ,what remains.
Page 10 - From these theorems may readily be found any one of these five parts ; the two extremes, the number of terms, the common difference, and the sum of all the terms, when any three of them are given, as in the following Problems : PROBLEM I.
Page 328 - Proportional, when the ratio of the first to the second, is equal to the ratio of the second to the third.
Page 11 - SUBTRACT the less extreme from the greater, and divide the difference by 1 more than the number of means required to be found...

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