Page images
PDF
EPUB

Ex. 6. A lends to B 1001, how much is B in debt after A has taken goods of him to the amount of 731 128 410 ?

Ans. 261 78 71d. 7 Suppose that my rent for half a year is 201 128, and that I have laid out for the land-lax 148 6d, and for several repairs 11 38 3d, what have I to pay of my half-year's rent?

Ans. 181 148 2 d. 8. A trader failing, owes to A 352 78 6d, to B 912 138 dd, to C 532 74d, to D 871 58, and to E 1112 38 5jd. When this happened, he had by him in cash 231 78 5d, in wares 532 118 10d, in household furniture 631 178 73d, and in recoverable book-debts 251 78 5d. What will his creditors lose by him, suppose these things delivered to them? Ans. 2121 5s 3 d.

EXAMPLES OF WEIGHTS, MEASURES, &c.

TROY WEIGHT. APOTHECARIES' WEIGHT.
1.
2.

3.
lb oz dwt gr
lb oz dwt gr

lb oz dr scr gr From 9

2 12 10 7 10 4 17 73 4 7 0 14 Take 5 4 6 17 3 7 16 12 29 5 3 19

[blocks in formation]
[blocks in formation]

20. The line of defence in a certain polygon being 236 yards, and that part of it which is terminated by the curtain and shoulder being 146 yards 1 foot 4 inches ; what then was the length of the face of the bastion ? Ans. 89 yds 1 ft 8 in.

COMPOUND MULTIPLICATION.

COMPOUND MULTIPLICATION shows how to find the amount of any given number of different denominations repeated a certain proposed number of times ; which is performed by the following rule.

Set the multiplier under the lowest number of the multiplicand, and draw a line below it.-Multiply the numbor in the lowest denomination by the multiplier, and find how many units of the next higher denomination are contained in the product, setting down what remains. - In like manner, multiply the number in the next denomination, and to the product carry or add the units, before found, and find how many units of the next higher denomination are in this

amount,

amount, which carry in like manner to the next product, setting down the overplus.- Proceed thus to the highest denomination proposed : so shall the last product, with the several remainders, taken as one compound number, be the whole amount required. --The method of Proof, and the reason of the Rule, are the same as in Simple Multiplication.

EXAMPLES OF MONEY.

1. To find the amount of 8lb of Tea, at 58 8.d per lb.

d
5 81

8

8

[blocks in formation]

8

2 d 2. 41b of Tea, at 78 8d

per
1b.

Ans. 1 10 8 3. 6 ib of Butter, at 9 d per lb.

Ans. 0 4 9 4. 7 lb of Tobacco, at 188d per Ib.

Ans. 011 11 5. 9 Stone of Beef, at 28 7{d per st.

Ans. 1 1 0 6. 10 cwt of Cheese, at 21 178 10d per cwt. Ans. 28 18 4 7. 12 cwt of Sugar, at 31 78 4d per cwt. Ans. 40 8 0

CONTRACTIONS.

I. If the multiplier exceed 12, multiply successively by its component parts, instead of the whole number at once.

[blocks in formation]

1 2. 20 cwt of Hops, at 41 78 2d per cwt. Ans. 87 3. 24 tons of Hay, at 31 78 6d per ton.

Ans. 81 4. 45 ells of Gloth, at 18 6d per ell.

Ans. 3

[ocr errors][merged small][merged small][merged small]

i d Ex.5. 63 gallons of Oil, at 28 3d per gall. Ans. 7 1 9

6. 70 barrels of Ale, at ll 45 per barrel Ans. 84 0
7. 84 quarters of Oats, at ll 128 8d per qr. Ans. 137 4 0
8. 96 quarters of Barley, at 17 38 4d per qr. Ans. 112 O
9. 120 days' Wages, at 58 9d per day. Ans. 34 10 0
10. 144 reams of Paper, at 138 4d per ream. Ans. 96 0

[ocr errors]
[ocr errors]

II. If the multiplier cannot be exactly produced by the multiplication of simple numbers, take the nearest number to it, either greater or less, which can be so produced, and multiply by its parts, as before.—Then multiply the given multiplicand by the difference between this assumed number and the multiplier, and add the product to that before found, when the assumed number is less than the multiplier, but subtract the same when it is greater.

[blocks in formation]

8

2 d 2. 29 quarters of Corn, at 21 58 31d per qr. Ans. 65 12 104 3. 53 loads of Hay, at 31 158 2d per load. Ans. 199 3 10 4. 79 bushels of Wheat,at 118 5d per bush.Ans. 45

6 101 5. 97 casks of Beer, at 128 2d per

cask. Ans. 59 0 2 6. 114 stone of Meat, at 158 330 per stone. Ans. 87 5 74

EXAMPLES OF WEIGHTS AND MEASURES.

1. 16 oz dwt gr 28 7 14 10

5

2.
1b oz dr sc
2 6 3 2

gr
10
8

3. cwt qr lb oz 29 2 16 14

12

[blocks in formation]

COMPOUND DIVISION teaches how to divide a number of several denominations by any given number, or into any num. ber of equal parts ; as follows:

Place the divisor on the left of the dividend, as in Simple Division.—Begin at the left-hand, and divide the number of the highest denomination by the divisor, setting down the quotient in its proper place. If there be any remainder after this division, reduce it to the next lower denomination, which add to the number, if any, belonging to that denomination, and divide the sum by the divisor.--Set down again this quotient, reduce its remainder to the next lower denomination again, and so on through all the denominations to the last.

EXAMPLES OF MONEY.

1. Divide 2371 88 6d by 2.
2

d
2) 237 8

6 118 14

3 the Quotient.

2. Divide

VOL. I.

« PreviousContinue »