A treatise on mensuration, both in theory and practice. The second edition, with many additionsG. G. J.&J. Robinson, 1788 - 16 pages |
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Page 54
... shall have n√√3 × : 3.32 3.5.33 + + 3 + 2 2.3.23 2.4.5.25 2.4.6.7.27 & c = 60 ; and hence the fum of the infinite feries I 3 + + 2 3.32 3.5-33 + 2.3.23 2.4.5.25 & c will be 2.4.6.7.27 60 3.14159 & c = and is , therefore , 12√3 1803 3 ...
... shall have n√√3 × : 3.32 3.5.33 + + 3 + 2 2.3.23 2.4.5.25 2.4.6.7.27 & c = 60 ; and hence the fum of the infinite feries I 3 + + 2 3.32 3.5-33 + 2.3.23 2.4.5.25 & c will be 2.4.6.7.27 60 3.14159 & c = and is , therefore , 12√3 1803 3 ...
Page 55
... shall have √ 4a2 ( aa + bb - cc ) √4a2b2 — ( aa + bb — cc ) 2 - = bb b for the value of the faid perpendicular to the base , and hence √4a2b2 ( aa + bb - cc ) 2 b 2 abc : 24 :: c : = r the - √4a2b2 − ( aa + bb — cc ) 2 radius of ...
... shall have √ 4a2 ( aa + bb - cc ) √4a2b2 — ( aa + bb — cc ) 2 - = bb b for the value of the faid perpendicular to the base , and hence √4a2b2 ( aa + bb - cc ) 2 b 2 abc : 24 :: c : = r the - √4a2b2 − ( aa + bb — cc ) 2 radius of ...
Page 57
... shall have , by taking the former of these from the latter , A - P = 22 P - a - a3 13a5 + 24r3640r5 = a3 24-3 3r from the former , A 72 + 7as a & c . But , from the first feries , 3845 P- P + = & c ; hence , by fubtracting the latter a ...
... shall have , by taking the former of these from the latter , A - P = 22 P - a - a3 13a5 + 24r3640r5 = a3 24-3 3r from the former , A 72 + 7as a & c . But , from the first feries , 3845 P- P + = & c ; hence , by fubtracting the latter a ...
Page 115
... ( 1 − y2 ) y2 + n - 1.n - 2 - n - 3 - n - 4 ( 1 - y2 ) 2 ya & c = 0 . 2.3.4.5 And by writing any particular value for n , the root of the equation The multiplier for the pentagon being 1.7204774 , we shall Sect . 1. ] REGULAR POLYGONS . 115.
... ( 1 − y2 ) y2 + n - 1.n - 2 - n - 3 - n - 4 ( 1 - y2 ) 2 ya & c = 0 . 2.3.4.5 And by writing any particular value for n , the root of the equation The multiplier for the pentagon being 1.7204774 , we shall Sect . 1. ] REGULAR POLYGONS . 115.
Page 116
... shall have , 2t I + tt y y I - 1 instead of y , in the - First , 12-261 ° + 143t8-245t + 14314 — 2612 + 1 = 0 , an equation whofe root is the tangent of the CAP ( 643 ° ) in the heptagon . Secondly , 16-4524 + 47612 176810 + 27013176816 ...
... shall have , 2t I + tt y y I - 1 instead of y , in the - First , 12-261 ° + 143t8-245t + 14314 — 2612 + 1 = 0 , an equation whofe root is the tangent of the CAP ( 643 ° ) in the heptagon . Secondly , 16-4524 + 47612 176810 + 27013176816 ...
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