Elements of Geometry: Being Chiefly a Selection from Playfair's Geometry |
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Page 87
... diameter & c . Q. E. D. PROPOSITION XVI . THEOREM . A straight line drawn perpendicular to the diameter of a circle , from one extremity of it , is a tangent to the circle . Let ABC be a circle , the centre of which GEOMETRY . BOOK I. 87.
... diameter & c . Q. E. D. PROPOSITION XVI . THEOREM . A straight line drawn perpendicular to the diameter of a circle , from one extremity of it , is a tangent to the circle . Let ABC be a circle , the centre of which GEOMETRY . BOOK I. 87.
Page 88
... tangent to a circle . First , let A be a given point without the given circle BCD ; it is required to draw a straight line from A which shall touch the circle . Find the centre E of the circle ( 1. 3 ) , and join AE ; from the centre E ...
... tangent to a circle . First , let A be a given point without the given circle BCD ; it is required to draw a straight line from A which shall touch the circle . Find the centre E of the circle ( 1. 3 ) , and join AE ; from the centre E ...
Page 89
... tangent . Let the straight line DE touch the circle ABC in the point C ; find the centre F , and join FC ; FC is perp . to DE . A For , if FC be not perp . to DE , from the point F draw FBG perp . to DE ; then because FGC is a right ...
... tangent . Let the straight line DE touch the circle ABC in the point C ; find the centre F , and join FC ; FC is perp . to DE . A For , if FC be not perp . to DE , from the point F draw FBG perp . to DE ; then because FGC is a right ...
Page 98
... tangent to a circle from a given point with- out it . Let DGH be the given circle , and A any point without it , from which it is required to draw a tangent . Find the centre C , and join AC , and on AC as a diameter describe the circle ...
... tangent to a circle from a given point with- out it . Let DGH be the given circle , and A any point without it , from which it is required to draw a tangent . Find the centre C , and join AC , and on AC as a diameter describe the circle ...
Page 99
... tangents AG , AK , drawn from the same point A without a circle , are equal . For the triangles AGC , AKC , having ... tangent and chord is equal to the angle in the seg- ment of the circle , which is on the opposite side of the chord ...
... tangents AG , AK , drawn from the same point A without a circle , are equal . For the triangles AGC , AKC , having ... tangent and chord is equal to the angle in the seg- ment of the circle , which is on the opposite side of the chord ...
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Elements of Geometry: Being Chiefly a Selection From Playfair's Geometry John Playfair No preview available - 2023 |
Elements of Geometry: Being Chiefly a Selection From Playfair's Geometry John Playfair No preview available - 2023 |
Common terms and phrases
ABC is equal ABCD alternate angles angle ABC angle ACB angle BAC angles AGH angles equal base ABC bases and altitudes bisect centre chord circumference cone Consequently cylinder demonstrations described diagonals diameter divided draw equal angles equal arches equal bases equal circles equal to AC equiangular Euclid's Euclid's Elements exterior angle fore four quantities four right angles geometry given point given straight line gles greater Hence homologous sides intersect KLMN Let ABC meet opposite angles opposite side paral parallel lines parallel to CD parallelogram parallelopipeds perp perpendicular plane polygon prism Prop pyramid Q. E. D. COR Q. E. D. PROPOSITION radius rectangle contained right angled triangle Scholium segments semicircle side AC similar similar triangles solid square straight line &c subtended tangent THEOREM triangle ABC vertex wherefore
Popular passages
Page 36 - Any two sides of a triangle are together greater than the third side.
Page 80 - If a straight line be divided into any two parts, the square of the whole line is equal to the squares of the two parts, together with twice the rectangle contained by the parts.
Page 42 - To draw a straight line through a given point parallel to a given straight line. Let A be the given point, and BC the given straight line...
Page 30 - To bisect a given finite straight line, that is, to divide it into two equal parts. Let AB be the given straight line : it is required to divide it intotwo equal parts.
Page 20 - LET it be granted that a straight line may be drawn from any one point to any other point.
Page 38 - Problem. At a given point in a given straight line to make a rectilineal angle equal to a given rectilineal angle.
Page 113 - Wherefore also the angle BAD is equal to the angle CAD : Therefore the angle BAC is cut into two equal angles by the straight line AD.
Page 24 - DE ; the point B shall coincide with the point E, because AB is equal to DE; and AB coinciding with DE, AC shall coincide...
Page 36 - The greater angle of every triangle is subtended by the greater side, or has the greater side opposite to it.