The Elements of Euclid, the parts read in the University of Cambridge [book 1-6 and parts of book 11,12] with geometrical problems, by J.W. Colenso1846 |
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Page 8
... angle BAC equal to the angle EDF : the base BC shall be equal to the base EF , and the triangle ABC to the triangle DEF , and the other angles shall be equal , each to each , to which the equal sides are opposite , viz . the angle ABC ...
... angle BAC equal to the angle EDF : the base BC shall be equal to the base EF , and the triangle ABC to the triangle DEF , and the other angles shall be equal , each to each , to which the equal sides are opposite , viz . the angle ABC ...
Page 12
... angle BCD : Again , because BC is equal to BD the angle BCD is equal to the angle BDC : but it has been proved to be ... BAC shall be equal to the angle EDF . B For , if the triangle ABC be applied to the 12 EUCLID'S ELEMENTS .
... angle BCD : Again , because BC is equal to BD the angle BCD is equal to the angle BDC : but it has been proved to be ... BAC shall be equal to the angle EDF . B For , if the triangle ABC be applied to the 12 EUCLID'S ELEMENTS .
Page 13
... angle BAC coincides with the angle EDF , and is equal to it . Wherefore , If two triangles & c . Q. E. D. PROP . IX . PROB . To bisect a given rectilineal angle , that is , to divide it into two equal angles . Let BAC be the given ...
... angle BAC coincides with the angle EDF , and is equal to it . Wherefore , If two triangles & c . Q. E. D. PROP . IX . PROB . To bisect a given rectilineal angle , that is , to divide it into two equal angles . Let BAC be the given ...
Page 14
... angle DAF is equal to the angle EAF : Wherefore the given rectilineal angle BAC is bisected by the straight line AF . Q. E. F. PROP . X. PROB . To bisect a given finite straight line , that is , to divide it into two equal parts . Let ...
... angle DAF is equal to the angle EAF : Wherefore the given rectilineal angle BAC is bisected by the straight line AF . Q. E. F. PROP . X. PROB . To bisect a given finite straight line , that is , to divide it into two equal parts . Let ...
Page 19
... angles . Let ABC be a triangle , and let its side BC be pro- duced to D : the exterior angle ACD is greater than either of the interior opposite angles CBA , BAC . Bisect AC in E ( 1. 10 ) , join BE and produce it to F , making EF equal ...
... angles . Let ABC be a triangle , and let its side BC be pro- duced to D : the exterior angle ACD is greater than either of the interior opposite angles CBA , BAC . Bisect AC in E ( 1. 10 ) , join BE and produce it to F , making EF equal ...
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The Elements of Euclid, the Parts Read in the University of Cambridge [Book ... Euclides No preview available - 2016 |
Common terms and phrases
ABCD adjacent angles angle ABC angle ACB angle BAC angle BCD angle EDF angle equal base BC BC is equal centre chord circle ABC circumference cuts the circle diameter double draw equal angles equal to F equiangular equilateral triangle equimultiples exterior angle fore given circle given line given point given straight line gnomon greater ratio inscribed intersection isosceles triangle less Let ABC Let the straight lines be drawn lines drawn meet multiple opposite angles opposite sides parallel to BC parallelogram pentagon perpendicular plane polygon PROB produced proportionals Q.E.D. PROP rectangle contained rectilineal figure remaining angle right angles right-angled triangle segment semicircle shew shewn square of AC straight line &c straight line AB THEOR touches the circle triangle ABC twice the rectangle Wherefore
Popular passages
Page 42 - To a given straight line to apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.
Page 4 - Let it be granted that a straight line may be drawn from any one point to any other point.
Page 33 - F, which is the common vertex of the triangles: that is », together with four right angles. Therefore all the angles of the figure, together with four right angles are equal to twice as many right angles as the figure has sides.
Page 62 - If a straight line be divided into two equal parts, and also into two unequal parts; the rectangle contained by the unequal parts, together with the square of the line between the points of section, is equal to the square of half the line.
Page 22 - If from the ends of a side of a triangle, there be drawn two straight lines to a point within the triangle, these shall be less than the other two sides of the triangle, but shall contain a greater angle.
Page 58 - If there be two straight lines, one of which is divided into any number of parts, the rectangle contained by the two straight lines is equal to the rectangles contained by the undivided line, and the several parts of the divided line.
Page 146 - ... may be demonstrated from what has been said of the pentagon : and likewise a circle may be inscribed in a given equilateral and equiangular hexagon, and circumscribed about it, by a method like to that used for the pentagon.
Page 194 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Page 2 - A circle is a plane figure contained by one line, which is called the circumference, and is such, that all straight lines drawn from a certain point within the figure to the circumference are equal to one another : 16.
Page 69 - To divide a given straight line into two parts, so that the rectangle contained by the whole, and one of the parts, may be equal to the square of the other part.