Elements of Algebra |
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Page 17
... remainder : thus 2 is a measure of 2 a ; ax is a measure of a x2 ; a + b is a measure of ( a + b ) a . A common measure of two or more quantities is any factor which will divide them all without remainder ; and their greatest common ...
... remainder : thus 2 is a measure of 2 a ; ax is a measure of a x2 ; a + b is a measure of ( a + b ) a . A common measure of two or more quantities is any factor which will divide them all without remainder ; and their greatest common ...
Page 19
... remainder c , then a = pb + c ; Suppose c is contained in b , q times with remainder d , then b = qc + d ; Suppose d is contained in c , r times with remainder 0 , then = rd . b ) a ( p pb c ) b ( g qc d ) c ( r Now is , b ; dr 0 d ...
... remainder c , then a = pb + c ; Suppose c is contained in b , q times with remainder d , then b = qc + d ; Suppose d is contained in c , r times with remainder 0 , then = rd . b ) a ( p pb c ) b ( g qc d ) c ( r Now is , b ; dr 0 d ...
Page 20
... remainder , and so on till nothing remains ; the last divisor will be the greatest common measure . " 9 This rule would apply to the examples in Art . X. LEAST COMMON MULTIPLE A common multiple of any quantities is a quantity which ...
... remainder , and so on till nothing remains ; the last divisor will be the greatest common measure . " 9 This rule would apply to the examples in Art . X. LEAST COMMON MULTIPLE A common multiple of any quantities is a quantity which ...
Page 37
... remainder ; he then found that he had left exactly eleven pounds ; what money had he at first ? Ans . £ 110 . 3 6. A grazier spent of his money in horses , in oxen , and 10 of the remainder in sheep ; after which he found he had £ 98 ...
... remainder ; he then found that he had left exactly eleven pounds ; what money had he at first ? Ans . £ 110 . 3 6. A grazier spent of his money in horses , in oxen , and 10 of the remainder in sheep ; after which he found he had £ 98 ...
Page 41
... , and multiplying it by b , we obtain 3a2b + 3ab2 + b3 , which is equal to the remainder . * In the ordinary arithmetical process these two ciphers would be omitted . The process is as follows , 3a2 + 3ab + EVOLUTION 41.
... , and multiplying it by b , we obtain 3a2b + 3ab2 + b3 , which is equal to the remainder . * In the ordinary arithmetical process these two ciphers would be omitted . The process is as follows , 3a2 + 3ab + EVOLUTION 41.
Common terms and phrases
a²x² ALGEBRA annuity arithmetic mean arithmetic series arithmetical progression b² a² Binomial Theorem C.E. Illustrated C₁ cent cloth boards coefficients common ratio compound interest containing cube root denominator digits Divide divisor Edition ENGINEERING equal Examples expression Extract the square find the number Find the sum fraction gallons geometric mean geometrical progression given greatest common measure harmonic means harmonic series Hence J. F. HEATHER logarithms miles Multiply nth term number of combinations number of shot number of terms number of variations permutations present value Prop quadratic quotient RALPH TATE reciprocal equation remainder Rudimentary Treatise shillings side square pile square root Subtract surd things taken total number unknown quantities Woodcuts x²y
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