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acres angle Answer base bearing called centre chord circle Co-line Co-tang column contained decimal difference Dift direct Diſt distance divided division draw drawn east edge equal EXAMPLE feet field field-book figures four fourth give given greater ground half height Hence inches laid land length less logarithm manner measure meridian method multiplied needle object observe off-sets opposite parallel parallelogram perches perpendicular plain plane Plate pole PROB proportion quantity quotient radius reduce remainder right angles right line root scale Secant sect side sights sine square station stationary suppose survey taken tangent theo third triangle triangle ABC true turn variation whence whole
Page 32 - The angle in a semicircle is a right angle ; the angle in a segment greater than a semicircle is less than a right angle ; and the angle in a segment less than a semicircle is greater than a right angle.
Page 94 - C' (89) (90) (91) (92) (93) 112. In any plane triangle, the sum of any two sides is to their difference as the tangent of half the sum of the opposite angles is to the tangent of half their difference.
Page 23 - Four quantities are said to be in proportion when the product of the extremes is equal to that of the means : thus if A multiplied by D, be equal to B multiplied by C, then A is said to be to B as C is to D.
Page 95 - TO THEIR DIFFERENCE ; So IS THE TANGENT OF HALF THE SUM OF THE OPPOSITE ANGLES', To THE TANGENT OF HALF THEIR DIFFERENCE.
Page 37 - ABDE+ACGF the sum of the squares —BKLH-\-KCML, the sum of the two parallelograms or square BCMH; therefore the sum of the squares on AB and AC is equal to the square on BC.
Page 24 - Things that are equal to one and the same thing, are equal to each other. 2. Every whole is greater than its part. % 3. Every whole is equal to all its parts taken together. 4 If to equal things, equal things be added, the whole will be equal. 5. If from equal things, equal things be deducted the remainders will be equal.
Page 36 - XIII. •All parallelograms on the same or equal bases and between the same parallels...
Page 182 - VI. To find the content of a triangular piece of ground, Multiply the base by half the perpendicular, or the perpendicular by half the base ; or take half the product of the base into the perpendicular. The reason hereof is plain, from cor.