The first book of Euclid's Elements, simplified, explained and illustrated, by W. Trollope1847 |
From inside the book
Results 1-5 of 32
Page 11
... proved . 2. The enunciation repeated with reference to a particular figure . 3. The construction , by means of ... proving a contrary sup- position to be absurd . - The enunciation of a Problem proposes certain data , or premises , from ...
... proved . 2. The enunciation repeated with reference to a particular figure . 3. The construction , by means of ... proving a contrary sup- position to be absurd . - The enunciation of a Problem proposes certain data , or premises , from ...
Page 14
... prove that AD = BC . By property of the O , AC To each of these equals add AB ; 2. To prove that AE = BE . ( AB = ) BD ( Def . 15 ) . .. AD = BC ( Ax . 2 ) . Again , by property of O , AE = AD , and BE ( Def . 15 ) ; .. AE = BE ( Ax . 1 ) ...
... prove that AD = BC . By property of the O , AC To each of these equals add AB ; 2. To prove that AE = BE . ( AB = ) BD ( Def . 15 ) . .. AD = BC ( Ax . 2 ) . Again , by property of O , AE = AD , and BE ( Def . 15 ) ; .. AE = BE ( Ax . 1 ) ...
Page 15
... prove that BG AL . For same reason , DG = DL ( Def . 15 ) . Now , by the construction , DB = DA ; traction , BG AL ( AX . 3 ) . 3. .. also AL = BC ( AX . 1 ) . .. by sub- Wherefore , from the gn . pt . A , a st . line AL has been drawn ...
... prove that BG AL . For same reason , DG = DL ( Def . 15 ) . Now , by the construction , DB = DA ; traction , BG AL ( AX . 3 ) . 3. .. also AL = BC ( AX . 1 ) . .. by sub- Wherefore , from the gn . pt . A , a st . line AL has been drawn ...
Page 17
... prove each case , but it is superfluous to insert them here . We are now , however , in a condition to give the following general solution of Prop . A. The principle is carried yet further in Prop . XXII . PROP . B. PROB . GEN . ENUN ...
... prove each case , but it is superfluous to insert them here . We are now , however , in a condition to give the following general solution of Prop . A. The principle is carried yet further in Prop . XXII . PROP . B. PROB . GEN . ENUN ...
Page 18
... , AC shall fall upon DF , because the BAC EDF . ( Hyp . ) 3. Also , pt . c shall coincide with pt . F , be- cause AC = DF . ( Hyp . ) 4. Since therefore the pt . в was proved to coincide with the pt . E , the base BC 18 EUCLID.— -BOOK I.
... , AC shall fall upon DF , because the BAC EDF . ( Hyp . ) 3. Also , pt . c shall coincide with pt . F , be- cause AC = DF . ( Hyp . ) 4. Since therefore the pt . в was proved to coincide with the pt . E , the base BC 18 EUCLID.— -BOOK I.
Common terms and phrases
ABCD adjacent angle contained base BC bisect CD Prop coincide Const CONST.-In CONST.-Join CONST.-Let DEMONST.-Because DEMONST.-For demonstration diam diameter draw EBCF ENUN ENUN.-If ENUN.-Let ABC ENUN.-To ENUN.-To describe equal sides equilateral Euclid EUCLID'S ELEMENTS exterior four rt given point given straight line interior and opposite interior opposite isosceles join Let ABC line be drawn line drawn meet opposite angles opposite sides parallel parallelogram perpendicular Post PROB produced Proposition proved rectilineal figure rhombus right angles side BC square take any pt THEOR THEOR.-If Theorem trapezium trapezium ABCD vertical Wherefore XXIX XXXI XXXII XXXIV XXXVIII
Popular passages
Page 58 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...
Page 24 - Upon the same base, and on the same side of it, there cannot be two triangles, that have their sides which are terminated in one extremity of the base equal to one another, and likewise those which are terminated in the other extremity, equal to one another.
Page 34 - If, at a point in a straight line, two other straight lines, upon the opposite sides of it, make the adjacent angles together equal to two right angles, these two straight lines shall be in one and the same straight line.
Page 6 - When a straight line standing on another straight line makes the adjacent angles equal to one another, each of the angles is called a right angle; and the straight line which stands on the other is called a perpendicular to it.
Page 109 - If the square described upon one of the sides of a triangle, be equal to the squares described upon the other two sides of it; the angle contained by these two sides is a right angle.
Page 9 - Parallel straight lines are such as are in the same plane, and which being produced ever so far both ways, do not meet.
Page 99 - To a given straight line to apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.
Page 49 - If, from the ends of the side of a triangle, there be drawn two straight lines to a point within the triangle, these shall be less than, the other two sides of the triangle, but shall contain a greater angle. Let...
Page 104 - In any right-angled triangle, the square which is described upon the side subtending the right angle, is equal to the squares described upon the sides which contain the right angle.
Page 6 - A circle is a plane figure contained by one line, which is called the circumference, and is such that all straight lines drawn from a certain point within the figure to the circumference, are equal to one another.