A Supplement to the Elements of Euclid |
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Page 5
... centres are all in the straight line that bisects at right angles the straight line joining the two given points . 7 ... centre , at the distance DA , which ( constr . E. xv . Def . 1. ) is equal to the given semi- diameter , will pass ...
... centres are all in the straight line that bisects at right angles the straight line joining the two given points . 7 ... centre , at the distance DA , which ( constr . E. xv . Def . 1. ) is equal to the given semi- diameter , will pass ...
Page 19
... centre , at the same distance , describe another circle ; lastly , from D as a centre , at a distance equal to that of A , B , describe another circle , cutting the circle last described in C ; join B , C. BC is pa- rallel to AD . For ...
... centre , at the same distance , describe another circle ; lastly , from D as a centre , at a distance equal to that of A , B , describe another circle , cutting the circle last described in C ; join B , C. BC is pa- rallel to AD . For ...
Page 29
... centre , and the half of any hypotenuse for its radius . For , the bisections of the hypotenuses will , each of them , ( Supp . xxix . 1. ) be at a distance from the common vertex equal to the half of one of the equal hypotenuses ; i ...
... centre , and the half of any hypotenuse for its radius . For , the bisections of the hypotenuses will , each of them , ( Supp . xxix . 1. ) be at a distance from the common vertex equal to the half of one of the equal hypotenuses ; i ...
Page 95
... at right angles , by the straight line joining their centres . Let the circle ABC , of which the centre is K , DE K B- L and the circle ADC , of which the centre is L , cut one another in the points A ,, C ; and A ...
... at right angles , by the straight line joining their centres . Let the circle ABC , of which the centre is K , DE K B- L and the circle ADC , of which the centre is L , cut one another in the points A ,, C ; and A ...
Page 96
... centre , to draw a chord which shall be bisected in that point . Let A be a given point within the circle BCD : B A C K It is required to draw , through A , a chord of the circle BCD , which shall be bisected in the point A. Find ( E. i ...
... centre , to draw a chord which shall be bisected in that point . Let A be a given point within the circle BCD : B A C K It is required to draw , through A , a chord of the circle BCD , which shall be bisected in the point A. Find ( E. i ...
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Common terms and phrases
AB² ABCD AC² aggregate angle equal arch bisect centre chord circle ABC circumference constr describe a circle describe the circle diameter distance divided draw E equi equiangular equilateral finite straight line fourth proportional given circle given finite straight given point given ratio given square given straight line greater ratio hypotenuse inscribed isosceles triangle join K less Let AB Let ABC lines be drawn manifest meet the circumference parallel to BC parallelogram polygon PROBLEM produced PROP rectangle contained rectilineal figure remaining sides required to draw rhombus right angles segment semi-diameter shewn straight line joining tangent THEOREM touch the circle trapezium wherefore xlvii xvii xxix xxvi xxviii xxxi xxxii xxxiv
Popular passages
Page 277 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Page 560 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. D c A' D' Hyp. In triangles ABC and A'B'C', ZA = ZA'. To prove AABC = ABxAC. A A'B'C' A'B'xA'C' Proof. Draw the altitudes BD and B'D'.
Page 564 - Wherefore, in equal circles &c. QED PROPOSITION B. THEOREM If the vertical angle of a triangle be bisected by a straight line which likewise cuts the base, the rectangle contained by the sides of the triangle is equal to the rectangle contained by the segments of the base, together with the square on the straight line which bisects the angle.
Page 178 - If a straight line be bisected, and produced to any point ; the rectangle contained by the whole line thus produced, and the part of it produced, together with the square...
Page 557 - ... line and the extremities of the base have the same ratio which the other sides of the triangle have to one another: and if the segments of the base...
Page 539 - If there be two straight lines, one of which is divided into any number of parts, the rectangle contained by the two straight lines is equal to the rectangles contained by the undivided line, and the several parts of the divided line.
Page 325 - IF an angle of a triangle be bisected by a straight line, which likewise cuts the base ; the rectangle contained by the sides of the triangle is equal to the rectangle contained by the segments of the base, together with the square of the...
Page 550 - AB into two parts, so that the rectangle contained by the whole line and one of the parts, shall be equal to the square on the other part.
Page 555 - And if the first have a greater ratio to the second, than the third has to the fourth, but the third the same ratio to the fourth, which the fifth has to the sixth...
Page 17 - ... angles equal; and conversely if two angles of a triangle are equal, two of the sides are equal. 3. If two triangles have the three sides of one equal to the three sides of the other, each to each, do you think the two triangles are alike in every respect ? 4. If two triangles have the three angles of one equal to the three angles of the other, each to each, do you think the two triangles are necessarily alike in every respect ? 5. Draw two triangles, the angles of one being equal to the angles...