 | Charles Hutton - Mathematics - 1807 - 464 pages
...MULTIPLY the perimeter of the polygon, or sum of its sides, by the perpendicular drawn from its centre on one of its sides, and take half the product for the area*. Ex. I. To find the area of the regular pentagon, each sidfebeing 25 feet, and the perpendicular from... | |
 | Charles Hutton - Mathematics - 1811 - 494 pages
...MULTIPLY the perimeter of the polygon, or sum of its sides, by the perpendicular drawn from its centre on one of its sides, and take half the product for the area *. . EX. 1. To find the area of a regular pentagon, each side being 25 feet, and the perpendicular... | |
 | Charles Hutton - Mathematics - 1822 - 616 pages
...MULTIPLY the perimeter of the polygon, or sum of its sides, by the perpendicular drawn from its centre on one of its sides, and take half the product for the area.* Ex. I. To find the area of the regular pentagon, each side being 25 feet, and the perpendicular from... | |
 | William Templeton (engineer.) - 1833 - 224 pages
...the Area of any regular Polygon. RULE. — Multiply the sum of its sides by a per pendicular drawn from its centre to one of its sides, and take half the product for the area. Or, Multiply the square of the side of a polygon (from three to twelve sides) by the numbers in the... | |
 | Frederick Augustus Griffiths - 1839 - 348 pages
...polygon.—Multiply the perimeter (or sum of the sides) of the polygon by the perpendicular drawn from its centre on one of its sides, and take half the product for the area. Or, Multiply the area of one of the triangles by the number of sides of the polygon, and the product... | |
 | 1837 - 800 pages
...' polygon. Rule. — Multiply the sum of its sides liy I a perpendicular drawn from its centre to i one of its sides, and take half the product ' for the area. Example 1 — Required the area of the regular pentagon, A 11 cn F, each side | being 7.5, and perpendicular,... | |
 | Nathan Scholfield - 1845 - 894 pages
...of the figure, or sum of its sides, and multiply it by the perpendicular falling from its centre on one of its sides, and take half the product for the area. £lJU.59675-:-2=lU75.29S375 square feet, •he area of the pentagon ABDEFA required. APB Scholium 1.... | |
 | William Templeton - Mathematics - 1846 - 518 pages
...find the area of any regular polygon. RULE. — Multiply the sum of its sides by a perpendicular drawn from its centre to one of its sides, and take half the product fqr the area. Or, Multiply the square of the side of a polygon (from three to twelve sides) by the... | |
 | Charles William Hackley - Geometry - 1847 - 248 pages
...Multiply the perimeter of the polygon, or sum of its sides, by the perpendicular drawn from its center on one of its sides, and take half the product for the area.* * The demonstration of this is given in th. 73. Ex. 1. To find the area of the regular pentagon, each... | |
 | Charles Haslett - Engineering - 1855 - 482 pages
...find the area of any regular polygon, RULE. Multiply the sum of its sides by a perpendicular drawn from its centre to one of its sides, and take half the product for the area. Or, multiply the square of the side of a polygon (from three to twelve sides) by the numbers in the... | |
| |
PROBLEM V. To find the area of any regular polygon. RULE. Multiply the sum of its sides by a perpendicular drawn from its centre to one of its sides, and take half the product for the area. Or, multiply the square of the side of a polygon (from three... 
