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the root of the coefficient may be extract
, the gauare root of (=e*=*a?
Thus, the square root of a45a?=a? *3 2 270°#3a1 =za su * Va+b12=a* 6
Faib=ab 6. The exponents of the letters may not be multiples of the index of the root, and then they become fractions; and when the root of the coefficient cannot be extracted, it may also be expressed by a fractional exponent, its original index being underfood to be 1.
Thus, I ab=4a
: 171x?=73a}x='Vāxa}x.: As evolution is the reverse of involution, the reason of the rule is evident.
The root of any fraction is found by extracting that root out of both numerator and denominator.
Case II. When the quantity is compound. 1. To extract the square root.
1. The given quantity is to be na
ranged according to the powers of the letters, as in divison,
si Thus, in the example a+2ab +67, the quantities are ranged in this manner..
2. The square root is to be extracted out of
the first term (by preceding rules), which gives the first part of the root fought. Subtract its square from the given quan: tity, and divide the first term of the remainder by double the part already found, and the quotient is the second term of the
Thus, in this example, the remainder is 2ab +62; and 2ab being divided by 2a, the double of the part found, gives +b for the second part of the root.
3. Add this second part to double of the first, and multiply their fum by-the second part:
-> Subtraat tbe product from the last remain
der, and if nothing remain, the square root is obtained. But, if there is a remainder, it muft be divided by the double of the
parts already found, and the quotient will and give the third part of the root; and fo on. lity brasi
In the laft example, it is obvious that 2+5 is the square root fought.
1. The entire operation is as follows:
01 2ab +6
The reason of this rule appears, from the composition of a squarea idius ti bisa, ish
kuinnst ó is gradi zetua banido 25 it to 2. To extract tahývother roots to liar sirsitoup sai heo huwa borto area Rule Range this quantity, according to the
dimensions of its letters, and extract the faid root out of the firf term, and that Shall be the first member of the root required. Then raise this root to a dimension
lower by unit, than the number that denominates the root required, and multiply the power that arises, by that number itself: divide the second term of the given quantity by the product, and the quotient. Shall give the second member of the root required. In like manner are the other parts to be found, by considering those already got as making one term.
Thus, the fifth root of as +5a4b+10a2b2 +10a2b3+5ab4+b(a+b