Mathematical Exercises ...1867 |
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Page 13
... Volume of cylinder = r2h . Volume of frustum of pyramid or cone h = 1/1 { A + √ Ad + 8 } 3 height of h , perpendicular height ; A , d areas of ends . Volume of sphere 4 3 = πρ . πλ Volume of segment of sphere = ( h2 + 3r2 ) , r being 6 ...
... Volume of cylinder = r2h . Volume of frustum of pyramid or cone h = 1/1 { A + √ Ad + 8 } 3 height of h , perpendicular height ; A , d areas of ends . Volume of sphere 4 3 = πρ . πλ Volume of segment of sphere = ( h2 + 3r2 ) , r being 6 ...
Page 18
... coefficient of volume of solid of revolution , dv = πу2 . dx Differential coefficient of surface of solid of revolution , ds ds = 2πу . dx dx { 1+ dy dx Radius of curvature , p = dzy Parabola , p = 2 ( a + x ) dx2 18 FORMULA .
... coefficient of volume of solid of revolution , dv = πу2 . dx Differential coefficient of surface of solid of revolution , ds ds = 2πу . dx dx { 1+ dy dx Radius of curvature , p = dzy Parabola , p = 2 ( a + x ) dx2 18 FORMULA .
Page 20
... volume of solid of revolution , dv == Y ?. dx Differential coefficient of surface of solid of revolution , ds ds = 2xу . dx dx Radius of curvature , p = { 1 + ( dx ) dy day 2 ( a + x ) Parabola , p = dx2 18 FORMULE .
... volume of solid of revolution , dv == Y ?. dx Differential coefficient of surface of solid of revolution , ds ds = 2xу . dx dx Radius of curvature , p = { 1 + ( dx ) dy day 2 ( a + x ) Parabola , p = dx2 18 FORMULE .
Page 21
... Volumes of Solids . sin le e X2 v = f = ydx + 0 ; V2 = V1 = * f * 1 yde . 2 - = T x1 ; Pyramid , v = ¦ a2h ; Cone , v = = 1 } { ar2h . 4π73 Sphere , v = 3 1 Paraboloid v = circumscribing cylinder ; 4 Prolate spheroid , v = · παδ ' ; 4 ...
... Volumes of Solids . sin le e X2 v = f = ydx + 0 ; V2 = V1 = * f * 1 yde . 2 - = T x1 ; Pyramid , v = ¦ a2h ; Cone , v = = 1 } { ar2h . 4π73 Sphere , v = 3 1 Paraboloid v = circumscribing cylinder ; 4 Prolate spheroid , v = · παδ ' ; 4 ...
Page 36
... volume of the pulp to be lost in the process of drying ? XVIII . 1. Reduce 4 tons 5 cwts . 3 qrs . 27 lbs . to ounces , and 495 yards to ells . Prove the results . 2. Divide £ 395 14s . 0ąd . by 125 , and prove the result . 3. Divide ...
... volume of the pulp to be lost in the process of drying ? XVIII . 1. Reduce 4 tons 5 cwts . 3 qrs . 27 lbs . to ounces , and 495 yards to ells . Prove the results . 2. Divide £ 395 14s . 0ąd . by 125 , and prove the result . 3. Divide ...
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acres angle axis ball base binomial theorem bisected body CALC cent centre of gravity circle coefficient of friction compound interest cube cubic curve determine diameter Divide dwts ellipse equal equilibrium Express Extract the square feet Find the area Find the centre Find the distance Find the equation find the height Find the number Find the value fluid forces acting given horizontal plane inches inclined plane inscribed intersect latus rectum length logarithms lowest terms Multiply parabola parallel particle perpendicular plane triangle pressure Prove pulleys radius rectangular recurring decimal Reduce right-angled sides simple interest Simplify sin² sine smooth Solve the equations square root straight line string surface tangent tons tower TRIG velocity vertex vertical vulgar fractions weight yards
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