Euclid's Elements of plane geometry [book 1-6] explicitly enunciated, by J. Pryde. [With] Key1860 |
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Page 1
... Given ABC an isosceles triangle , of which the vertical angle ACB is bisected by the line CD , to prove that AB is ... point in the latter is equally distant from the extremities of the former ; and any point not situated in the latter ...
... Given ABC an isosceles triangle , of which the vertical angle ACB is bisected by the line CD , to prove that AB is ... point in the latter is equally distant from the extremities of the former ; and any point not situated in the latter ...
Page 2
... point equally distant from two given points . Let AB be the given line , and PQ the given points , to find a point , as C in AB , that shall be equidis- tant from the points P and Q. Join P and Q , bisect PQ in D , and draw CD ...
... point equally distant from two given points . Let AB be the given line , and PQ the given points , to find a point , as C in AB , that shall be equidis- tant from the points P and Q. Join P and Q , bisect PQ in D , and draw CD ...
Page 3
... given points . Let MN be the given points , O the middle of MN , and XY any line through O ; also let OX = OY , and ... point O , the same reasoning will apply . EXERCISE V. - THEOREM . Of all lines that can be drawn from a given point ...
... given points . Let MN be the given points , O the middle of MN , and XY any line through O ; also let OX = OY , and ... point O , the same reasoning will apply . EXERCISE V. - THEOREM . Of all lines that can be drawn from a given point ...
Page 4
Euclides James Pryde. EXERCISE VI . - THEOREM . If from every point of a given line , the lines drawn to each of two given points on opposite sides of the line are equal ; prove that the straight line joining the given points will be ...
Euclides James Pryde. EXERCISE VI . - THEOREM . If from every point of a given line , the lines drawn to each of two given points on opposite sides of the line are equal ; prove that the straight line joining the given points will be ...
Page 5
... point in the line that bisects a given angle is equidistant from the sides of the angle . Let AB , AC , be the sides of an angle BAC , which is bisected by the line AD ; then , if from any point O in AD , the perpendiculars OE , OF be ...
... point in the line that bisects a given angle is equidistant from the sides of the angle . Let AB , AC , be the sides of an angle BAC , which is bisected by the line AD ; then , if from any point O in AD , the perpendiculars OE , OF be ...
Other editions - View all
Euclid's Elements of Plane Geometry [Book 1-6] Explicitly Enunciated, by J ... Euclides,James Pryde No preview available - 2023 |
Euclid's Elements of Plane Geometry [book 1-6] Explicitly Enunciated, by J ... Euclides,James Pryde No preview available - 2018 |
Common terms and phrases
AB² AC² AD² altitude angle ACB BC² BD² bisects the angle centre chord circumference consequently construction cut harmonically describe a circle diagonals diameter dicular draw equal angles equiangular equilateral triangle EXERCISE exterior angle figure find a point find the locus given angle given circle given line given point greater half hence hypotenuse intersection isosceles triangle Let ABC line joining lines be drawn lines drawn opposite sides Pages parallelogram perpen perpendicular Price produced quadrilateral radius rectangle rectangle contained required locus required point required to prove required triangle right angles right-angled triangle Scholium segments semiperimeter side AC square straight line tangent touch triangle ABC Trig vertex vertical angle whence wherefore Wood-cuts
Popular passages
Page 72 - ABC be a triangle, and DE a straight line drawn parallel to the base BC ; then will AD : DB : : AE : EC.
Page 19 - The line joining the middle points of two sides of a triangle is parallel to the third side and equal to half of the third side.
Page 55 - All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Page 26 - Prove that three times the sum of the squares on the sides of a triangle is equal to four times the sum of the squares on the lines drawn from the vertices to the middle points of the opposite sides.
Page 73 - If three quantities are in continued proportion, the first is to the third as the square of the first is to the square of the second. Let a : b = b : c. Then, 2=*. b с Therefore, ^xb. = ^x± b с bb Or °r
Page 58 - EH parallel to AB or DC, and through F draw FK parallel to AD or BC ; therefore each of the figures, AK, KB, AH, HD, AG, GC, BG...
Page 29 - The sum of the squares of the sides of a quadrilateral is equal to the sum of the squares of the diagonals...
Page 24 - If from the middle point of one of the sides of a right-angled triangle, a perpendicular be drawn to the hypotenuse, the difference of the squares on the segments into which it is divided, is equal to the square on the other side.
Page 2 - Of all triangles having the same vertical angle, and whose bases pass through a given point, the least is that whose base is bisected in the given point.