## A Royal Road to Geometry: Or, an Easy and Familiar Introduction to the Mathematics. ... By Thomas Malton. ... |

### From inside the book

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Page 99

Take a fine , smooth Cord or string , and , having fixed two Pins in F and G , carry

the string round both Pins , and draw it , on both sides , to the

where , fix a Pencil , and revolve it around , on the two Pins , keeping the String at

...

Take a fine , smooth Cord or string , and , having fixed two Pins in F and G , carry

the string round both Pins , and draw it , on both sides , to the

**Point**C , or D ;where , fix a Pencil , and revolve it around , on the two Pins , keeping the String at

...

Page 208

If two Right Lines are drawn , from any two

, to the same

Angle , when they meet in the

If two Right Lines are drawn , from any two

**Points**in the Circumference of a Circle, to the same

**Point**iñ à Tangent to that Circle ; those Lifles will make the greatestAngle , when they meet in the

**Point**of contact : 10. I. Let A and B be the**Points**... Page 209

A and B are the assumed

required to find the

to that

Right ...

A and B are the assumed

**Points**; and , let CD be a given Right Line . It isrequired to find the

**Point**D , fo , that , if two Right Lines AD and BD be E drawn ,to that

**Point**, the Angle ADB , ihall be greater than any other Angle , made D byRight ...

Page 345

From any given

that

BEC , draw , at pleasure , the Right Line BC , and , from A , B draw the Right ...

From any given

**Point**, * to draw a Right Line perpendicular to a Plane , in whichthat

**point**is not fituated . Let A be the given**Point**, and BEC a Plane . In the PlaneBEC , draw , at pleasure , the Right Line BC , and , from A , B draw the Right ...

Page 346

Or, an Easy and Familiar Introduction to the Mathematics. ... By Thomas Malton. ...

Thomas Malton. PROBLEM II . 12Euclid . From a

a Right Line perpendicular to the Plane . D B C Let A be the given

Or, an Easy and Familiar Introduction to the Mathematics. ... By Thomas Malton. ...

Thomas Malton. PROBLEM II . 12Euclid . From a

**Point**given in a Plane , to drawa Right Line perpendicular to the Plane . D B C Let A be the given

**Point**, in the ...### What people are saying - Write a review

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A Royal Road to Geometry: Or, an Easy and Familiar Introduction to the ... Thomas Malton No preview available - 2016 |

### Common terms and phrases

ABCD added alſo Altitudes analogous Area Baſe becauſe biſected Book called Center Chord Circle Circumference common Cone conf conſequently Conſtruction contained cuting Cylinder Demonſtration deſcribe Diagonal Diameter difference divided draw drawn equal Euclid evident extreme fame Feet Figure firſt formed four fourth given given Line greater half Hence Inches inſcribed join laſt leſs manner mean meaſure multiplied muſt oppoſite parallel Parallelogram Parallelopiped Pentagon perpendicular Plane Point Poligon Priſm Prob PROBLEM produced Proportion Propoſition proved Pyramid Quantities Radius Ratio Rect Rectangle reſpectively Right Angles Right Line ſame ſame Ratio ſay ſeeing Segment Sides ſimilar Solid ſome Sphere Square ſuch Surface taken Terms THEOREM third thoſe touch Triangle uſe wherefore whole whoſe

### Popular passages

Page 124 - When you have proved that the three angles of every triangle are equal to two right angles...

Page 221 - All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides.

Page 285 - EG, let fall from a point in the circumference upon the diameter, is a mean proportional between the two segments of the diameter DS, EF (p.

Page 284 - IN a right-angled triangle, if a perpendicular be drawn from the right angle to the base, the triangles on each side of it are similar to the whole triangle, and to one another.

Page 186 - From this it is manifest, that if one angle of a triangle be equal to the other two, it is a right angle, because the angle adjacent to it is equal to the same two; and when the adjacent angles are equal, they are right angles.

Page 248 - To express that the ratio of A to B is equal to the ratio of C to D, we write the quantities thus : A : B : : C : D; and read, A is to B as C to D.

Page 161 - In any triangle, if a line be drawn from the vertex at right angles to the base; the difference of the squares of the sides is equal to the difference of the squares of the segments of the base.

Page 160 - In any isosceles triangle, the square of one of the equal sides is equal to the square of any straight line drawn from the vertex to the base plus the product of the segments of the base.

Page 250 - Ratios that are the same to the same ratio, are the same to one another. Let A be to B as C is to D ; and as C to D, so let E be to F.

Page 124 - Angles, taken together, is equal to Twice as many Right Angles, wanting four, as the Figure has Sides.