## A Royal Road to Geometry: Or, an Easy and Familiar Introduction to the Mathematics. ... By Thomas Malton. ... |

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Page 48

deduced the general Rule for mea . suring all Parallelograms ; which is , to

multiply the Base ; any Side ( as AD ) by its perpendicular height , ( CD ) For it

gives the ...

**Hence**it is evident , that two Spaces may have the fame Area ... From**hence**isdeduced the general Rule for mea . suring all Parallelograms ; which is , to

multiply the Base ; any Side ( as AD ) by its perpendicular height , ( CD ) For it

gives the ...

Page 122

COR :

equal to four Right Angles . 2. All the Angles which can be made aboạt a Point

are equal to four Right Angles . Τ Η Ε Ο R Ε Μ III . If a Right Line , cuting two

Right ...

COR :

**Hence**, if two Right Lines intersect each other , the Angles they make areequal to four Right Angles . 2. All the Angles which can be made aboạt a Point

are equal to four Right Angles . Τ Η Ε Ο R Ε Μ III . If a Right Line , cuting two

Right ...

Page 127

Angie is bitected according to the 2nd method , Prob . gth ; viz by making two

Triangles , congrous with each other , T HE 0 . THEOREM VIII . 4. Euclid . , 2 b ...

**Hence**, an Angle is made equal to a given Angle , as in Pr . 4 ; and**hence**, anAngie is bitected according to the 2nd method , Prob . gth ; viz by making two

Triangles , congrous with each other , T HE 0 . THEOREM VIII . 4. Euclid . , 2 b ...

Page 129

another Triangle , and the contained Angle , of one , be greater or less than the

contained Angle of the other , the remaining Side will allo be greater or less ; and

...

**Hence**, if two sides of one Triangle be equal , respectively , to two sides ofanother Triangle , and the contained Angle , of one , be greater or less than the

contained Angle of the other , the remaining Side will allo be greater or less ; and

...

Page 25

Parallelopipeds are Prisms ) having equal height , have that Proportion to each

other , which is between their Bases . And , having equal Bases , they are

consequently ...

**Hence**it is manifest , that all Parallelopipeds , or Prisms whatever , ( forParallelopipeds are Prisms ) having equal height , have that Proportion to each

other , which is between their Bases . And , having equal Bases , they are

consequently ...

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### Common terms and phrases

ABCD added alſo Altitudes analogous Area Baſe becauſe biſected Book called Center Chord Circle Circumference common Cone conf conſequently Conſtruction contained cuting Cylinder Demonſtration deſcribe Diagonal Diameter difference divided draw drawn equal Euclid evident extreme fame Feet Figure firſt formed four fourth given given Line greater half Hence Inches inſcribed join laſt leſs manner mean meaſure multiplied muſt oppoſite parallel Parallelogram Parallelopiped Pentagon perpendicular Plane Point Poligon Priſm Prob PROBLEM produced Proportion Propoſition proved Pyramid Quantities Radius Ratio Rect Rectangle reſpectively Right Angles Right Line ſame ſame Ratio ſay ſeeing Segment Sides ſimilar Solid ſome Sphere Square ſuch Surface taken Terms THEOREM third thoſe touch Triangle uſe wherefore whole whoſe

### Popular passages

Page 124 - When you have proved that the three angles of every triangle are equal to two right angles...

Page 221 - All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides.

Page 285 - EG, let fall from a point in the circumference upon the diameter, is a mean proportional between the two segments of the diameter DS, EF (p.

Page 284 - IN a right-angled triangle, if a perpendicular be drawn from the right angle to the base, the triangles on each side of it are similar to the whole triangle, and to one another.

Page 186 - From this it is manifest, that if one angle of a triangle be equal to the other two, it is a right angle, because the angle adjacent to it is equal to the same two; and when the adjacent angles are equal, they are right angles.

Page 248 - To express that the ratio of A to B is equal to the ratio of C to D, we write the quantities thus : A : B : : C : D; and read, A is to B as C to D.

Page 161 - In any triangle, if a line be drawn from the vertex at right angles to the base; the difference of the squares of the sides is equal to the difference of the squares of the segments of the base.

Page 160 - In any isosceles triangle, the square of one of the equal sides is equal to the square of any straight line drawn from the vertex to the base plus the product of the segments of the base.

Page 250 - Ratios that are the same to the same ratio, are the same to one another. Let A be to B as C is to D ; and as C to D, so let E be to F.

Page 124 - Angles, taken together, is equal to Twice as many Right Angles, wanting four, as the Figure has Sides.